javascript - coffee-script 编译后,怎么才能避免出现不需要出现的return呢?
天蓬老师
天蓬老师 2017-04-10 15:18:48
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coffeescript 新手,请多多指教。

coffee上的代码是:

refine = (wheat,chaff...) -> console.log "The best: #{wheat}" console.log "The rest: #{chaff.join(',')}" refine 'one','two','three','four'

编译出来后:

(function() { var refine, __slice = [].slice; refine = function() { var chaff, wheat; wheat = arguments[0], chaff = 2 <= arguments.length ? __slice.call(arguments, 1) : []; console.log("The best: " + wheat); return console.log("The rest: " + (chaff.join(','))); }; refine('one', 'two', 'three', 'four'); }).call(this);

refine函数里面最后一行,多了return,实际中应该不需要这个return的,为什么会被这样编译出来呢?
需要去掉吗?怎么去掉?
不需要去掉吗?为什么?

天蓬老师
天蓬老师

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reply all (1)
迷茫

最后一行写一个return或者undefined

refine = (wheat,chaff...) -> console.log "The best: #{wheat}" console.log "The rest: #{chaff.join(',')}" return refine 'one','two','three','four'

or

refine = (wheat,chaff...) -> console.log "The best: #{wheat}" console.log "The rest: #{chaff.join(',')}" undefined refine 'one','two','three','four'

http://stackoverflow.com/questions/7391493/is-there-any-way-to-not-ret...

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