Is there an easy way to get those records whose value is different from other records
P粉163951336
P粉163951336 2024-04-04 21:59:30
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So, I have the record in my database:

id Date Time Name level
0 2022-03-22 23:18:01 John 615
1 2022-03-22 23:17:01 John 616
2 2022-03-22 23:16:02 John 616
3 2022-03-22 23:15:01 John 616
4 2022-03-22 23:14:01 John 617
5 2022-03-22 23:13:01 John 617
6 2022-03-22 23:12:01 John 616
7 2022-03-22 23:11:01 John 617
8 2022-03-22 23:10:02 John 618
9 2022-03-22 23:09:01 John 618

As a result I want to get these values ​​where the next "lvl" is different from the previous "lvl". I mean, I want to get the result record with id:

0 - Because it's the first one,

1 - Because lvl is not equal to 0,

2,3 - skipped because lvl is the same as 1

4 - Because lvl is different from 1,

5 - skipped because lvl is the same as 4,

6 - Because the level is different from 5,

7 - Because the level is different from 6,

8 - Because the level is different from 7,

9 - Skip.

P粉163951336
P粉163951336

reply all(1)
P粉164942791

This seems to be a good fit for lag analytic functions (using MySQL 8):

with keep as (
  select *, if(id=Min(id) over() or level != lag(level) over(order by id), 1, 0) keepme
  from t
)
select id
from keep
where keepme=1;

Sample Fiddle

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