I'm trying to build a regular expression that replaces all symbols "$$" with some HTML tags, like <someTag></someTag>.
I used this regex, but it doesn't cover all cases:
$$(\S[^\*]+\S)$$
'aaa $3$$ c$ ddd'.replace(/$$(\S[^\*]+\S)$$/g, '<a1></a1>') // works 'aaa $3$$ c$ $$ddd$$'.replace(/$$(\S[^\*]+\S)$$/g, '<a1></a1>') // doesn't work, should be 'aaa <a1>123</a1> c$ <a1>ddd</a1>'
console.log('aaa $3$$ c$ ddd'.replace(/$$(\S[^\*]+\S)$$/g, '<a1></a1>')) // works
console.log('aaa $3$$ c$ $$ddd$$'.replace(/$$(\S[^\*]+\S)$$/g, '<a1></a1>')) // doesn't work, should be 'aaa <a1>123</a1> c$ <a1>ddd</a1>'
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Not a regex solution, but it works. Description: Split the string using the delimiter (
$$). Then create a new stringresultand insert each part of the array. It then checks whether the current index is odd or even, and adds a start tag (prefix) or end tag (suffix) as appropriate. I hope this helps!function replaceTag(string, delimiter, prefix, suffix){ let parts = string.split(delimiter); let result = ''; for(let index = 0; index ', '')); console.log(replaceTag('aaa $3$$ c$ $$ddd$$', '$$', '', ' '));The fastest way is to use the non-greedy point-to-point method:
/\$\$(.*?)\$\$/sghttps://regex101.com/r/upveAX/1
Using dot alone will always be faster since it doesn't rely on assertions or class structures,
This adds a 3x performance overhead.
console.log('aaa $3$$ c$ ddd'.replace(/$$(.*?)$$/sg, '