This warning tells you that the property you are trying to set is not listed at the top of the class.

When you run this command:

class database {

    public $username = "root";
    public $password = "pasword";
    public $port = 3306;

    public function __construct($params = array())
    {
        foreach ($params as $key => $value)
        {
            $this->{$key} = $value;
        }
    }
}

$db = new database(array(
    'database' => 'db_name',
    'server' => 'database.internal',
));

is roughly equivalent to this:

class database {

    public $username = "root";
    public $password = "pasword";
    public $port = 3306;
}

$db = new database;
$db->database = 'db_name';
$db->server = 'database.internal';

The warning is that there is no line in the class definition indicating that $db->database or $db->server exists.

Currently, they are dynamically created as untyped public properties, but in the future, you will need to declare them explicitly:

class database {
    public $database;
    public $server;
    public $username = "root";
    public $password = "pasword";
    public $port = 3306;

    public function __construct($params = array())
    {
        foreach ($params as $key => $value)
        {
            $this->{$key} = $value;
        }
    }
}

$db = new database(array(
    'database' => 'db_name',
    'server' => 'database.internal',
));

In some rare cases you actually want to say "the properties of this class are whatever properties I decide to add at runtime"; in that case you can use #[AllowDynamicProperties] Attributes, as shown below:

#[AllowDynamicProperties]
class objectWithWhateverPropertiesIWant {
    public function __construct($params = array())
    {
        foreach ($params as $key => $value)
        {
            $this->{$key} = $value;
        }
    }
}

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So the warning comes from the constructor adding a dynamic class attribute. It does seem like you are making something simple too complex if you don't have to pass the fields dynamically and authentically, so try something like this.

class database {

    public $username = "root";
    public $password = "pasword";
    public $port = 3306;
    public $database = 'db_name';
    public $server = 'database.internal';
}


$db = new database();

Is there any reason why you need dynamic parameters? You can also do this:

class database {

    public $username = "root";
    public $password = "pasword";
    public $port = 3306;
    public $database;
    public $server;

    public function __construct($params = array())
    {

        foreach ($params as $key => $value)
        {
            $this->{$key} = $value;
        }
    }
}

If you add parameters ahead of time, they are not dynamic, you are just assigning a value to something that already exists.

It should now work without any warnings.

$db = new database(array(
    'database' => 'db_name',
    'server' => 'database.internal',
));

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