Why am I unable to link the settings screen to the login/registration screen after clicking on the name and I keep getting the error "undefined is not a function"?
P粉399090746
P粉399090746 2023-09-16 10:45:09
0
1
579

I'm trying to do a simple task of jumping from one screen to another, but no matter what I do it doesn't work. I have installed react-navigation/stack and react-navigation/native-stack but neither of them work with my existing code, is it because of the tabs?

import { NavigationContainer } from '@react-navigation/native'; import { createStackNavigator } from '@react-navigation/stack'; import Tabs from './navigation/tabs'; import "react-native-url-polyfill/auto" import LogInSignUp from './SettingsScreen/LogInSignUp'; const Stack = createStackNavigator(); const App = () => { return (        ); }; export default App; import { Text, StyleSheet, View, Button, } from "react-native"; import { StatusBar } from "expo-status-bar"; const Settings = (navigation) => { return (    ); } const styles = StyleSheet.create({ container: { flex: 1, alignItems: 'center', justifyContent: 'center', }, }) export default Settings import React from 'react' import { StackActions } from '@react-navigation/native'; const LogInSignUp = (navigation) => { return ( 
LogInSignUp
) } export default LogInSignUp

I tried looking up tutorials that explain this problem, all their code looks like my code, just changing the name to my .js file, but nothing works.

P粉399090746
P粉399090746

reply all (1)
P粉342101652

Have you tried this hook

const navigation = useNavigation();

import {useNavigation} from '@react-navigation/native'; const Settings = () => { const navigation = useNavigation(); return (    ); }
    Latest Downloads
    More>
    Web Effects
    Website Source Code
    Website Materials
    Front End Template
    About us Disclaimer Sitemap
    php.cn:Public welfare online PHP training,Help PHP learners grow quickly!