Determine the maximum interval of time difference: PHP implementation in minutes, hours, days, weeks, etc.-PHP Chinese Network Q&A

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Determine the maximum interval of time difference: PHP implementation in minutes, hours, days, weeks, etc.

P粉287726308 2023-09-13 22:30:14

474

After calculating the time difference, how do I determine whether the difference is only minutes, hours, or days, weeks, months, years...?

$now = new DateTime('now'); $expire_date = date('Y-m-d H:i:s', strtotime('+ 3 weeks')); $expire_on = new DateTime($expire_date); $time_left = $now->diff($expires_on); *** 伪代码如下所示，展示了我想要实现的功能 if ($time_left < 1 小时) 显示分钟 elseif ($time_left < 1 天) 显示小时和分钟 elseif ($time_left < 1 周) 显示天、小时和分钟 elseif ($time_left < 1 月) 显示周、天、小时和分钟 elseif ($time_left < 1 年) 显示月、周、天、小时和分钟 endif ** 结束伪代码

As I quickly learned, I needed to clarify the question. I only want to display minimal information. For example: "39 minutes remaining" instead of "0 days, 0 hours, 39 minutes remaining".

P粉287726308

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P粉5614384072023-09-14 10:53:04 1 floor

https://www.php.net/manual/en/class.dateinterval.php- There are some properties in the DateInterval object ($time_left is one of them) so you can test them and see if they are greater than 0. I recommend starting with the largest.

For example:

$now = new DateTime('now'); $expire_date = date('Y-m-d H:i:s', strtotime('+3 weeks')); $expire_on = new DateTime($expire_date); $time_left = $now->diff($expire_on); echo format_interval($time_left); function format_interval($time_left) { $format_string = ""; $weeks = (int) ($time_left->d / 7); $days = (int) ($time_left->d - ($weeks * 7)); if ($time_left->y > 0) $format_string = "%y year(s), %m month(s), $weeks week(s), $days day(s), %h hour(s) and %i minute(s)"; elseif ($time_left->m > 0) $format_string = "%m month(s), $weeks week(s), $days day(s), %h hour(s) and %i minute(s)"; elseif ($weeks > 0) $format_string = "$weeks week(s), $days day(s), %h hour(s) and %i minute(s)"; elseif ($time_left->d > 0) $format_string = "$days day(s), %h hour(s) and %i minute(s)"; elseif ($time_left->h > 0) $format_string = "%h hour(s) and %i minute(s)"; elseif ($time_left->i > 0) $format_string = "%i minute(s)"; else $format_string = "%s second(s)"; return $time_left->format($format_string); }

Online demonstration:https://3v4l.org/BiYHD. Try adjusting$expire_dateand test the results you get.

NOTE: For some reason, the DateInterval class does not support telling you the week number. Above I assume dividing the number of days by 7 is enough to calculate the number of weeks. The remaining days must then be recalculated (minus the number of days in the distribution week).