How to upload files using Python's requests library?-PHP Chinese Network Q&A

I am using Python's requests library to perform a simple task, which is to upload a file. I've searched on Stack Overflow and no one seems to be having the same problem, where the file is not being received by the server:

import requests url='http://nesssi.cacr.caltech.edu/cgi-bin/getmulticonedb_release2.cgi/post' files={'files': open('file.txt','rb')} values={'upload_file' : 'file.txt' , 'DB':'photcat' , 'OUT':'csv' , 'SHORT':'short'} r=requests.post(url,files=files,data=values)

I filled in the value of the 'upload_file' keyword with my filename because if I left it blank it would read:

Error - You must select a file to upload!

Now I get:

The size of file file.txt is bytes, uploaded successfully! Query service results: There are 0 rows in total.

This only occurs if the file is empty. So I don't know how to send my file successfully. I know the file is valid because if I fill out the form manually and visit the site, it returns a nice list of matches, which is exactly what I want. I really appreciate all the tips.

Some other threads that are related (but don't solve my problem):

Use a Python script to send files via POST
http://docs.python-requests.org/en/latest/user/quickstart/#response-content
Use requests to upload files and send additional data
http://docs.python-requests.org/en/latest/user/advanced/#body-content-workflow

>>> import requests >>> open('file.txt', 'wb') # 创建一个空的演示文件 <_io.BufferedWriter name='file.txt'> >>> files = {'upload_file': open('file.txt', 'rb')} >>> print(requests.Request('POST', 'http://example.com', files=files).prepare().body.decode('ascii')) --c226ce13d09842658ffbd31e0563c6bd Content-Disposition: form-data; name="upload_file"; filename="file.txt" --c226ce13d09842658ffbd31e0563c6bd--

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P粉4222270232023-08-17 12:40:36 2 floor

(2018) The new Python requests library simplifies this process. We can use the 'files' variable to indicate that we want to upload a multi-part encoded file

url = 'http://httpbin.org/post' files = {'file': open('report.xls', 'rb')} r = requests.post(url, files=files) r.text

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P粉5904283572023-08-17 11:32:38 1 floor

Ifupload_filerefers to a file, use:

files = {'upload_file': open('file.txt','rb')} values = {'DB': 'photcat', 'OUT': 'csv', 'SHORT': 'short'} r = requests.post(url, files=files, data=values)

Thenrequestswill send a multipart form POST request body with theupload_filefield set to the contents of thefile.txtfile.

The file name will be included in the mime header of the specific field:

Please note thefilename="file.txt"parameter.

If you need more control, you can use tuples asfilesmapping values. The length of the tuple should be between 2 and 4. The first element is the file name, followed by the content, optionally including a mapping of the content-type header and other headers:

files = {'upload_file': ('foobar.txt', open('file.txt','rb'), 'text/x-spam')}

This will set an alternative filename and content type, omitting the optional headers.

If you want the entire POST request body to come from a file (no other fields are specified), do not use thefilesparameter and POST the file directly asdata. You may also want to set aContent-Typeheader, otherwise no header will be set. SeePython requests - POST data from a file.