PHP warning: cannot convert array to string

Question

I have this code in my file: if(is_array($_REQUEST))$cepl=implode('',$_REQUEST); Every few days I get the following warning in the php log: PHP warning: in / Line 76 of file.php, converting the array into a string, line 76 is: $cepl=implode('',$_REQUEST); I can't figure out what caused this warning? !

P粉449281068 · Answer

The definition of function implode is very roughly equivalent to the following code (this is just an example, not tested):

function not_really_implode($glue, $pieces) {
   $result = '';
   $first = true;
   foreach ( $pieces as $piece ) {
      if ( ! $first ) {
          $result .= $glue;
      }
      $pieceAsString = (string)$piece;
      $result .= $pieceAsString;
      $first = false;
   }
   return $result;
}

The key point is this line of code:

$pieceAsString = (string)$piece; - In order to combine the elements of the array, implode must each element one by oneConvert to string.

Now consider if

$pieces looked like this:

$pieces = [
   'one',
   ['two-a', 'two-b'],
   'three',
];

At some point in our loop we will have

$piece = ['two-a', 'two-b'] and try to convert it to a string - oops!

So the reason the warning appears is because within

your $_REQUEST array, there are other arrays. Several ways this could happen:

$_REQUEST can be written directly. For example, someone could write $_REQUEST['example'] = ['a', 'b'];
recognize certain notations in the input to represent arrays. For example, someone could access the URL /your-page.php?example[]=a&example[]=b, and $_REQUEST would be automatically populated as ['a', 'b '].

This brings up a very important reminder:

Never trust user input! It is very dangerous to make any assumptions about the content in $_REQUEST, because the input is under the control of the user, and the user may not be yours friend.