84669 person learning
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Can anyone help me to see how to convert the time format 20182800255 into 2018-02-08 00:02:55?
If the month, day and hour are 1 digit
First take out the time and then process it, example:
First take out the time and then process it, example:
## $a=date("m"); If ($ A/10 & LT; 1) {// Determine whether the month is zero $ b = $ a/10*10; Echo " Today is " . $b . ""; } ?>