javascript - js about time conversion and time addition and subtraction.
phpcn_u1582
phpcn_u1582 2017-07-05 10:40:20
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1. Conversion of time

默认

mounted () { this.HomePageDisplay(); var myDate = new Date(); var reg=/[\u4E00-\u9FA5]/g; this.latestS=myDate.toLocaleString().replace(/\//g,'-').replace(/:/g,'-').replace(/[ ]/g,"").replace(reg,''); console.log(this.latestS) },

I converted this.

What I want is 2017-07-05-04. .

2. Regarding the addition and subtraction of time.

1、2017-07-05-04 减去10个小时。 格式不变。。 2、 当前的小时减去10个小时。。 下面代码我写的。 给自己蠢哭了。 求指点。。


var timeData = [ myDate.getHours()-10, myDate.getHours()-9, myDate.getHours()-8, myDate.getHours()-7, myDate.getHours()-6, myDate.getHours()-5, myDate.getHours()-4, myDate.getHours()-3, myDate.getHours()-2, myDate.getHours()-1, myDate.getHours(), ];
phpcn_u1582
phpcn_u1582

reply all (4)
迷茫

For time processing, it is recommended to introduce the moment library. http://momentjs.com/docs/#/pa...

var t = moment().format('YYYY-MM-DD-HH'); console.log(t); //2017-07-03-18 var tsub = moment(t, 'YYYY-MM-DD-HH').subtract(10, 'hours').format('YYYY-MM-DD-HH'); console.log(tsub); //2017-07-03-08
    阿神
    1. If you need the format of 2017-03-14-04-50-08:

      var str = '2017/3/14 4:50:08 PM';
      var arr = str.split(/[ ^d ]+/g).map(item => (parseInt(item, 10) < ; 10 ? '0' + parseInt(item, 10) : item )).join('-');
      console.log(arr);

    2. As for the addition and subtraction of time, as mentioned above, it is actually good to introduce libraries such as moment.js into the project.

      洪涛
      Date.prototype.format = function(fmt) { var o = { "M+" : this.getMonth()+1, //月份 "d+" : this.getDate(), //日 "h+" : this.getHours(), //小时 "m+" : this.getMinutes(), //分 "s+" : this.getSeconds(), //秒 "q+" : Math.floor((this.getMonth()+3)/3), //季度 "S" : this.getMilliseconds() //毫秒 }; if(/(y+)/.test(fmt)) { fmt=fmt.replace(RegExp., (this.getFullYear()+"").substr(4 - RegExp..length)); } for(var k in o) { if(new RegExp("("+ k +")").test(fmt)){ fmt = fmt.replace(RegExp., (RegExp..length==1) ? (o[k]) : (("00"+ o[k]).substr((""+ o[k]).length))); } } return fmt; } new Date().format("yyyy-MM-dd hh:mm:ss");//"2017-07-03 17:01:35" 加减法用总的毫秒数计算,然后在转化成时间。
        我想大声告诉你

        Date.prototype.past = function(pattern, pastDays) {

        function zeroize(num) { return num < 10 ? "0" + num : num; }; var pastday = new Date((this - 0) - 1000 * 60 * 60 * 24 * pastDays); var pattern = pattern; // YYYY-MM-DD 或 MM-DD-YYYY 或 YYYY-MM-DD , hh : mm : ss var dateObj = { "Y": pastday.getFullYear(), "M": zeroize(pastday.getMonth() + 1), "D": zeroize(pastday.getDate()), "h": zeroize(pastday.getHours()), "m": zeroize(pastday.getMinutes()), "s": zeroize(pastday.getSeconds()) }; return pattern.replace(/YYYY|MM|DD|hh|mm|ss/g, function(match) { switch (match) { case "YYYY": return dateObj.Y; case "MM": return dateObj.M; case "DD": return dateObj.D; case "hh": return dateObj.h; case "mm": return dateObj.m; case "ss": return dateObj.s; }; });

        };
        var timeEnd = new Date();
        timeEnd = timeEnd.getFullYear() + '/' + (timeEnd.getMonth() + 1) + '/' + timeEnd.getDate() + ' ' + timeEnd. getHours() + ':' + timeEnd.getMinutes();
        You mean to push the current time forward 10 minutes, new Date(timeEnd).past('YYYY-MM-DD hh : mm : ss', 1/ (24*6));

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