How to compare two arrays in javascript
習慣沉默
習慣沉默 2017-06-26 10:52:07
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Array a

[{key:1,name:'name1'},{key:2,name:'name2'},{key:3,name:'name3'},{key:4,name:'name4'},{key:5,name:'name5'}]

Array b is part of array a

[{key:1,name:'name1'},{key:2,name:'name2'}]

Array c is modified based on array b

[{key:1,name:'name11'},{key:22,name:'name22'}]

Now the final result is needed: key:1 is modified, key:2 is deleted, key:3, key:4, key:5 are retained without change, key:22 is added

[{key:1,name:'name11'},{key:3,name:'name3'},{key:4,name:'name4'},{key:5,name:'name5'},{key:22,name:'name22'}]

Please tell me how to implement this logic

習慣沉默
習慣沉默

reply all (6)
滿天的星座

Do you want to compare or merge? Deepmerge is very convenient for merging

    Ty80
    //引入Lodash _.extend(_.difference(a, b), c)
      学习ing
      var a = [{key:1,name:'name1'},{key:2,name:'name2'},{key:3,name:'name3'},{key:4,name:'name4'},{key:5,name:'name5'}]; var b = [{key:1,name:'name1'},{key:2,name:'name2'}]; var c = [{key:1,name:'name11'},{key:22,name:'name22'}]; var d = []; d = $.extend(a,(b,c)); console.log(d);

      The extend method is similar to git’s merge
      Writing it like that should get the result you want in the end

        给我你的怀抱
        function compare(val1,val2){ if(val1 < val2){ return 1; }else if(val1 > val2){ return -1; }else{ return 0; } } var values = [1,2,50,60,10,20,80]; values.sort(compare); alert(values); //80,60,50,20,10,2,1
          typecho

          If you can’t find a good tool, or don’t want to pollute the namespace, then decouple the array, which should meet your requirements

          let a = [{ key: 1, name: 'name1' }, { key: 3, name: 'name3' }, { key: 2, name: 'name2' }, { key: 4, name: 'name4' }, { key: 5, name: 'name5' }]; let b = [{ key: 1, name: 'name1' }, { key: 2, name: 'name2' }]; let c = [{ key: 22, name: 'name22' }, { key: 1, name: 'name11' }]; let akeys = a.map(x => x.key); let aname = a.map(x => x.name) let bkeys = b.map(x => x.key)//1,2 let bname = b.map(x => x.name) let ckeys = c.map(x => x.key)//1,22 let cname = c.map(x => x.name) ckeys.forEach(function (key, index) { if (bkeys.includes(key)) a[akeys.indexOf(key)].name = cname[ckeys.indexOf(key)] else { a[akeys.indexOf(bkeys[1])].key = key a[akeys.indexOf(bkeys[1])].name = cname[ckeys.indexOf(key)] } }) console.log(a)
            漂亮男人

            I’ll give you a piece of code to imagine (only suitable for merging with arrays). Just take the following code to the console and output it

            function arrayExtends(){ var arrs = Array.prototype.slice.call(arguments); if(arrs.length < 2){ return arrs[0]; } var save = arrs.pop(), now; while(now = arrs.pop()){ for( var i = 0 , len = save.length; i < len; i++ ){ now[i] = save[i]; } save = now; } return save; } arrayExtends([1,2,3,6,7],[4,5,{hello:"world"}],[{key:1,name:"zz"}]);

            Then modify it to suit your needs:

            function arrayExtends(){ var arrs = Array.prototype.slice.call(arguments); if(arrs.length < 2){ return arrs[0]; } var save = arrs.pop(), now; while(now = arrs.pop()){ for( var i = 0 , len = save.length; i < len; i++ ){ now[i] = save[i]; } save = now; } var result = save.sort(function(a,b){ return a.key - b.key; }); return result; } arrayExtends([{key:1,name:"zz"}],[{key:2,name:"zz"},{key:3,name:"zz"}]);
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