android 不打开APP的情况下监听耳机插拔情况

扔个三星炸死你    2017-06-24 09:44:572楼

问题就是service进程如何存活

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天蓬老师    2017-06-24 09:44:571楼

import android.app.ActivityManager;
import android.app.Service;
import android.content.BroadcastReceiver;
import android.content.Context;
import android.content.Intent;
import android.content.IntentFilter;
import android.os.IBinder;
import android.util.Log;

import java.util.List;

public class HeadPhoneService extends Service {

public HeadPhoneService() {
}
@Override
public IBinder onBind(Intent intent) {
    // TODO: Return the communication channel to the service.
    throw new UnsupportedOperationException("Not yet implemented");
}

@Override
public void onCreate() {
    super.onCreate();
    Log.e("xxxx","service start");
}

@Override
public int onStartCommand(Intent intent, int flags, int startId) {
    IntentFilter intentFilter = new IntentFilter();
    intentFilter.addAction(Intent.ACTION_HEADSET_PLUG);
    registerReceiver(headsetReceiver, intentFilter);
    return super.onStartCommand(intent, flags, startId);
}

@Override
public void onDestroy() {
    Intent service = new Intent(this, HeadPhoneService.class);
    this.startService(service);
    super.onDestroy();
}

private BroadcastReceiver headsetReceiver=new BroadcastReceiver() {
    @Override
    public void onReceive(Context context, Intent intent) {
        String action = intent.getAction();
        if (Intent.ACTION_HEADSET_PLUG.equals(action)) {
            Log.e("xxxx","headsetchange");
            if (intent.hasExtra("state")) {
                int state = intent.getIntExtra("state", 0);
                if (state == 1) {

                } else if(state == 0){

                }
                Log.e("xxxx","headphone"+state);
            }
        }
    }
};

}

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