# coding: utf8 import time timestamp = time.time() - 3600 # 时间戳 print(time.strftime('%Y{y}%m{m}%d{d} %H{H}%M{M}', time.localtime(timestamp)).format(y='年', m='月', d='日', H='时', M='分'))

I have really researched a universal method. According to my Baidu Google, it seems that this is the only one in the world?

Without further ado, here are the solution principles and solutions:

Official documentation: https://docs.python.org/3/lib...

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classtime.`struct_time`¶

The type of the time value sequence returned bygmtime(),localtime(), andstrptime(). It is an object with a named tuple interface: values can be accessed by index and by attribute name. The following values are present:

Index	Attribute	Values
0	tm_year	(for example, 1993)
1	tm_mon	range [1, 12]
2	tm_mday	range [1, 31]
3	tm_hour	range [0, 23]
4	tm_min	range [0, 59]
5	tm_sec	range [0, 61]; see(2)instrftime()description
6	tm_wday	range [0, 6], Monday is 0
7	tm_yday	range [1, 366]
8	tm_isdst	0, 1 or -1; see below
N/A	tm_zone	abbreviation of timezone name
N/A	tm_gmtoff	offset east of UTC in seconds

Note that unlike the C structure, the month value is a range of [1, 12], not [0, 11].
In calls tomktime(),tm_isdstmay be set to 1 when daylight savings time is in effect, and 0 when it is not. A value of -1 indicates that this is not known, and will usually result in the correct state being filled in.
When a tuple with an incorrect length is passed to a function expecting astruct_time, or having elements of the wrong type, aTypeErroris raised.

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Looking at the documentation, you can see the tuple structure returned by time.localtime(). What I want to use is the year, month, day, hour, and the first 5, so here’s the code:

import time print('%s年%s月%s日 %s时%s分' % time.localtime(1497254119.69407)[:5])

Output:

2017年6月12日 15时55分

Done.

Please indicate the source when reprinting, thank you.