c++ - Can functions with the same name with different parameters in a derived class be declared as virtual functions

Question

When the base class and the derived class have functions with the same name, regardless of whether the number of parameters is the same or different, the subclass object will always directly call the function of the same name of the derived class. If you want to call the function of the same name of the base class, you need to use a base class pointer or reference. If you want to use the same calling form now, you can call the derived class...

欧阳克 · Answer

You can define it like this and then redefine it as needed in subclasses:

class Base {
public:
   virtual void print(int) = 0;
   virtual void print(float) = 0;
};

The root of this problem lies in how C++ finds the function. It must know the name and parameters of the function, so you must clearly define both. The return value can be vague. For example, the copy function in a subclass can return a subclass.