python - Looking for a method in def that can achieve the continue effect of calling this def to meet specific conditions (the title is not clear, please see the description in the question)-PHP Chinese Network Q&A

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python - Looking for a method in def that can achieve the continue effect of calling this def to meet specific conditions (the title is not clear, please see the description in the question)

过去多啦不再A梦 2017-05-27 17:39:54

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def con(x): if x==3: continue #会报错 def con2(x): if x == 4: continue #会报错 for i in range(0,10): con(i) con2(i) print(i)

What I mean is that if the conditions in def are met, the externally called for loop will continue. For example, in the example, if the value of i is 3 or 4, continue. Because there are many def methods called in for, and the actual scenario is much more complicated than the example, it feels like it is not very concise to judge the return value one by one. I would like to ask you if there is any way to realize this request of my brother. Thank you very much~

过去多啦不再A梦

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小葫芦2017-05-27 17:41:54 2 floor

You can affect the for loop by throwing a specific exception:

class Abort(Exception): pass def con(x): if x==3: raise Abort() def con2(x): if x == 4: raise Abort() for i in range(0,10): try: con(i) con2(i) except Abort: continue print(i)

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漂亮男人2017-05-27 17:41:54 1 floor

continue must be used together with for. You can try another implementation idea
such as:

def con(x): return True if x == 3 else False def con2(x): return True if x == 4 else False for i in range(0,10): lst = [ con(i), con2(i) ] if any(lst): continue print(i)

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