How to write rock-paper-scissors in python

Implement a small game of rock-paper-scissors where a person plays rock-paper-scissors with a computer, and learn Python's loop control statements and conditional judgment statements.

If rock, scissors, and paper are represented by numbers 0, 1, and 2 respectively. So how to determine who wins and who loses? (Recommended learning: Python video tutorial)

Although it is a simple rock-paper-scissors game, there is actually a lot of algorithmic thinking behind it, and many rules can be found.

If the variables user and computer are equal, it is a tie

If (user 1) is divided by 3 and the remainder is equal to computer, the user (person) gets Victory

In other cases, the computer wins

import random

# 初始化表示手势的变量
gesture = ['石头' , '剪刀', '布']
wins = 0
print("*********************")
print("石头剪刀布游戏\nVer 1.0.0 by YuZhou_1su\n")

# 进行5轮游戏
for i in range(5):
    # 输入玩家的手势
    print("*********************")
    print("0:石头 1:剪刀 2:布")
    print("*********************")
    user = int(input("请输入你想出的序号:\n"))
    if(user >= 0 and user <= 2):
        computer = random.randint(0, 2)
        print("玩家: {0}, 计算机: {1}".format(gesture[user], gesture[computer]))
        if user == computer:
            print("...平局! ")
        elif computer == (user + 1) % 3:
            print("...玩家获胜！ ")
            wins = wins + 1
        else:
            print("...计算机获胜！ ")
    else:
        print("***你输入的序号有错、请重新输入!***")

print("玩家获胜次数: %d " % wins)

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