PHP method to implement regular expression to determine whether it is a legal ID number-PHP Tutorial-php.cn

This article mainly introduces the method of PHP regularity to determine whether it is a legal ID number, involving PHP's regularity for numbers and string operation related skills. Friends in need can refer to the following

This article describes the examples PHP regular method to determine whether it is a legal ID number. Share it with everyone for your reference, the details are as follows:

/** * 判断是否为合法的身份证号码 * @param $mobile * @return int */ function isCreditNo($vStr){ $vCity = array( '11','12','13','14','15','21','22', '23','31','32','33','34','35','36', '37','41','42','43','44','45','46', '50','51','52','53','54','61','62', '63','64','65','71','81','82','91' ); if (!preg_match('/^([\d]{17}[xX\d]|[\d]{15})$/', $vStr)) return false; if (!in_array(substr($vStr, 0, 2), $vCity)) return false; $vStr = preg_replace('/[xX]$/i', 'a', $vStr); $vLength = strlen($vStr); if ($vLength == 18) { $vBirthday = substr($vStr, 6, 4) . '-' . substr($vStr, 10, 2) . '-' . substr($vStr, 12, 2); } else { $vBirthday = '19' . substr($vStr, 6, 2) . '-' . substr($vStr, 8, 2) . '-' . substr($vStr, 10, 2); } if (date('Y-m-d', strtotime($vBirthday)) != $vBirthday) return false; if ($vLength == 18) { $vSum = 0; for ($i = 17 ; $i >= 0 ; $i--) { $vSubStr = substr($vStr, 17 - $i, 1); $vSum += (pow(2, $i) % 11) * (($vSubStr == 'a') ? 10 : intval($vSubStr , 11)); } if($vSum % 11 != 1) return false; } return true; }

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