Detailed explanation of object comparison usage in PHP object-oriented

巴扎黑
Release: 2023-03-07 14:16:01
Original
1618 people have browsed it

Through cloning, we can understand the meaning of $a = $b and $a = clone $b. But in practical applications, we still need to determine whether the relationship between two objects is a clone or a reference. This can be done by using the comparison operators "==" and "===".

Operators "==" and "==="

When using comparisonOperator (==)Compare two object variables When, thecomparison principle is: If the attributes and attribute values of the two objects are equal, and the two objects are instances of the same class, then the two object variables are equal;

And if you use the congruentoperator (===), these two object variables must point to the same instance of a certain type (that is, the same object).

Let’s look at an example below:

type = $type; $this->age = $age; } } $dog1 = new Dog('二哈','2'); $dog2 = new Dog('二哈','2'); if($dog1 == $dog2){ echo '
$dog1 == $dog2'; } if($dog1 === $dog2){ echo '
$dog1 === $dog2 '; }else{ echo '
他们不能全等'; } echo '
'; $dog3 = $dog1; if($dog1 == $dog3){ echo '
$dog1 == $dog3'; } if($dog1 === $dog3){ echo '
$dog1 === $dog3 '; }else{ echo '
他们不能全等'; }
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Example analysis:

First we create a dog class and define the attribute type and age in the class , create a constructor. Then instantiate two identical classes, $dog1 and $dog2. Then compare the two instantiated classes. First use the comparison operator "==". We mentioned above the meaning of this symbol: when using the comparison operator (==) to compare two object variables, the comparison principle is: if the attributes and attribute values of the two objects are equal, and the two objects are the same instance of the class, then the two object variables are equal. First of all, it is judged that the attributes and attribute values of $dog1 and $dog2 are equal, and secondly, they are both instantiation results of the same Dog-like class, then the result is, $dog1==$dog2. But is the next judgment $dog1===$dog2 equal? Let's take a look at the conditions for the operator "===" to hold: And if you use the congruence operator (===), the two object variables must point to the same instance of a certain type (that is, the same object). This can only be true when the values compared on both sides of the operator "===" are the same object. $dog1 and $dog2 are two instances, not the same, so their "===" cannot be established. We give a condition, $dog3 = $dog1, and use the same method to compare and judge objects to see if it is true.

You can run the above example to see the results.

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