Home Backend Development PHP Tutorial Detailed explanation of the effect of the secondary linkage menu implemented by php mysql_php skills

Detailed explanation of the effect of the secondary linkage menu implemented by php mysql_php skills

May 21, 2018 am 11:18 AM
mysql php

the example in this article describes the secondary linkage menu effect implemented by php mysql. share it with everyone for your reference, the details are as follows:

<!--php+mysql二级联动-->
<html>
<head>
<meta http-equiv="content-type" content="text/html; charset=gb2312" />
<title>生成学院专业级联下拉菜单测试 </title>
</head>
<body>
<? //
/***********************************************
** 功 能: php+mysql+javascript实现学院专业二级级联下拉框
** 数据库:数据库名( dms)、数据表( colleges、 majors)
** 表 colleges中字段: college_id( id编号)、 name(学院名)
** 表 majors中的字段: major_id( id编号)、 college_id(学院 id)、 name(学院名)
** version 1.0
** 作 者: wu yaowen
***********************************************/
//****************** 连接选择数据库 ***************
$link = mysql_connect("localhost", "root", "123456")
 or die("could not connect : " . mysql_error());
mysql_select_db("dms") or die("could not select database");
//******************提取学院信息 ******************
$querycol = "select * from colleges order by college_id ";
mysql_query("set names 'gb2312'");
$result1 = mysql_query($querycol) or die("query failed : " . mysql_error());
$colleges = array();
while( $row1 = mysql_fetch_array($result1) )
{
 $colleges[] = $row1;
}
//print_r ($forum_data);
mysql_free_result($result1);
//**************获取专业信息 **************  
$querymaj = "select * from majors order by college_id desc";
mysql_query("set names 'gb2312'");
if( !($result2 = mysql_query($querymaj)) )
{
 die('could not query t_city list');
}
$majors = array();
while( $row2 = mysql_fetch_array($result2) )
{
 $majors[] = $row2;
}
mysql_free_result($result2);
?>
<!--************ javascript处理 college-onchange *************-->
<script language = "javascript">
var majorcount; // 存储专业记录条数
// form_majors[] 储存专业 major数据,如 {(1,1,电子商务 ),(4,1,计算机科学 ),(3,2,古典文学 )}
form_majors = new array();
<?php
  $num2 = count($majors); // $num2 获取专业表中记录的个数
?>
  majorcount = <?php echo $num2;?>;
<?
  for($j=0;$j<$num2;$j++) // 从 0开始取出上面 majors[]中存储的专业数据填充数组
{
?>
  form_majors[<?echo $j;?>] = new array("<?echo $majors[$j]['major_id'];?>","<?echo $majors[$j]['college_id'];?>","<?echo $majors[$j]['name'];?>");
<?php
}
?>
function changecollege(college_id)
{
  document.stu_add_form.major.length = 0;
  var id=id;
  var j;
  document.stu_add_form.major.options[0] = new option('==选择专业 ==',''); // label的 value为空 ' '
  for (j=0;j < majorcount; j++) // 从 0开始判断
  {
   if (form_majors[j][1] == college_id) // if college_id等于选择的学院的 id
   {
      document.stu_add_form.major.options[document.stu_add_form.major.length] = new option(form_majors[j][2], form_majors[j][0]);
   }
  }
}
</script>
<!--********************页面表单 *************************-->
<form name="stu_add_form" method="post">
选择: <select name="college" onchange="changecollege(document.stu_add_form.college.options[document.stu_add_form.college.selectedindex].value)" size="1">
<option selected>==请选择学院 ==</option>
<?php
$num = count($colleges);
for($i=0;$i<$num;$i++)
{
?>
<option value="<?echo $colleges[$i]['college_id'];?>"><?echo $colleges[$i]['name'];?></option>
<?
}
?>
</select>
<select name="major">
<option selected value="">==选择专业 ==</option>
</select>
</form>
</body>
</html>
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sql statement:

--
-- 表的结构 `colleges`
--
CREATE TABLE IF NOT EXISTS `colleges` (
`college_id` int(8) NOT NULL auto_increment COMMENT '学院编号自动增加',
`name` varchar(40) NOT NULL COMMENT '学院名称',
PRIMARY KEY (`college_id`),
UNIQUE KEY `name` (`name`)
) ENGINE=InnoDB DEFAULT CHARSET=gb2312 AUTO_INCREMENT=7 ;
--
-- 导出表中的数据 `colleges`
--
INSERT INTO `colleges` (`college_id`, `name`) VALUES
(4, '化学与化工学院'),
(1, '计算机与信息科学学院'),
(6, '美术学院'),
(2, '文学院'),
(5, '音乐学院'),
(3, '政治与公共管理学院');
--
-- 表的结构 `majors`
--
CREATE TABLE IF NOT EXISTS `majors` (
`major_id` int(8) NOT NULL auto_increment COMMENT '专业号,自动增加',
`name` varchar(40) NOT NULL COMMENT '专业名',
`college_id` int(8) default NULL COMMENT '所在学院',
`counsellor_id` int(10) default NULL COMMENT '辅导员',
PRIMARY KEY (`major_id`),
UNIQUE KEY `college_id` (`college_id`,`counsellor_id`)
) ENGINE=InnoDB DEFAULT CHARSET=gb2312 AUTO_INCREMENT=8 ;
--
-- 导出表中的数据 `majors`
--
INSERT INTO `majors` (`major_id`, `name`, `college_id`, `counsellor_id`) VALUES
(1, '电子商务', 1, 1),
(2, '音乐视唱', 5, 1),
(3, '古典文学', 2, 1),
(4, '计算机科学', 1, NULL),
(5, '自动化', 1, NULL),
(6, '现代文学', 2, NULL),
(7, '新闻写作', 2, NULL);
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i hope this article will be helpful to everyone in php programming.

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