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匹配URL参数正则表达式

WBOY
Release: 2016-06-13 11:10:37
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求一个匹配URL参数正则表达式
例如
http://www.sina.com.cn/sports/?p=3456

http://www.sina.com.cn/sports/?p=38923

http://www.sina.com.cn/sports/basktball/?p=878923

现在需要匹配出?p=里面的参数,就是加黑的部分
我使用的方法是,
^/?([a-z/]+)/\?p=([0-9]+)
能匹配前面的参数,但是没有办法匹配"?=p"后面的数字参数,请问这段正则表达怎么写呢? 谢谢!


------解决方案--------------------
preg_match('/p=(\d+)/',$s,$m);
echo $m[1];
------解决方案--------------------
2loou good
------解决方案--------------------
preg_match('/(?echo $match[0];
------解决方案--------------------
<br />(?<=p\=)\d+<br />
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