In php, read data from the database and return the data in json format. The specific method is as follows:
The first step is to define relevant variables
$servername = "localhost"; $username = "root"; $password = "root"; $mysqlname = "datatest"; $json = ''; $data = array(); class User { public $id; public $fname; public $lname; public $email; public $password; }
The second step is to link the database, the code is as follows:
// 创建连接 $conn = mysqli_connect($servername, $username, $password, $mysqlname);
The third step is to define the query statement and execute it. The code is as follows:
$sql = "SELECT * FROM userinfo"; $result = $conn->query($sql);
The fourth step is to obtain the queried data and place it in the pre-statement In the class, the final output is in json format
if($result){ //echo "查询成功"; while ($row = mysqli_fetch_array($result,MYSQL_ASSOC)) { $user = new User(); $user->id = $row["id"]; $user->fname = $row["fname"]; $user->lname = $row["lname"]; $user->email = $row["email"]; $user->password = $row["password"]; $data[]=$user; } $json = json_encode($data);//把数据转换为JSON数据. echo "{".'"user"'.":".$json."}"; }else{ echo "查询失败"; }
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