我模仿了题意，写了测试代码，结果如下

String html = "
mytextvalue
"; Matcher m = Pattern.compile("
(.*?)
").matcher(html); System.out.println(m.find()); //true System.out.println(m.groupCount()); //1 System.out.println(m.group(0)); //
mytextvalue
 System.out.println(m.group(1)); //mytextvalue

另外

// where does m.groupCount come from m = Pattern.compile("(group1)(group2)(group3)").matcher(html); System.out.println(m.groupCount()); //3

增加解释说明，
看源码的注释

/** * Returns the number of capturing groups in this matcher's pattern. * * 
 Group zero denotes the entire pattern by convention. It is not * included in this count. * * 
 Any non-negative integer smaller than or equal to the value * returned by this method is guaranteed to be a valid group index for * this matcher. 
 * * @return The number of capturing groups in this matcher's pattern */ public int groupCount() { return parentPattern.capturingGroupCount - 1; }

这里说得清楚，groupCount返回的是正则表达式的捕获分组的数量（捕获分组和非捕获分组是另外的知识点），groupCount的结果并不能说明匹配的结果。

要执行正则表达式匹配，需要执行find动作，看源码

public boolean find() { int nextSearchIndex = last; if (nextSearchIndex == first) nextSearchIndex++; // If next search starts before region, start it at region if (nextSearchIndex < from) nextSearchIndex = from; // If next search starts beyond region then it fails if (nextSearchIndex > to) { for (int i = 0; i < groups.length; i++) groups[i] = -1; return false; } return search(nextSearchIndex); }

这样的才会给Matcher内部的成员变量groups赋值，groups[i] = -1;
这样的之后在我们执行m.group(1)的时候我们才能获得捕获分组匹配到的内容。