mysql_select_db("zaiping", $con);
    $result = array();
    $rs = mysql_query("select count(*) as count from dept where deptName like $deptName");
    $row = mysql_fetch_array($rs);
    ChromePhp::log($row);
    $result["total"] = $row[0];

SQL command line executionselect count(*) as count from dept where deptName like $deptName tiada masalah Jika bilangan rekod >= 2, masalahnya ialah apabila terdapat 1 data yang sepadan, $result["total"]=0 Kenapa bukan 1? Terima kasih