Python 26进制计算实现方法

# -*- coding:utf-8 -*- 
''''' 
Created on 2013-3-29 
@author: naughty 
''' 
dict={} 
dict['A']=1 
dict['B']=2 
dict['C']=3 
dict['D']=4 
dict['E']=5 
dict['F']=6 
dict['G']=7 
dict['H']=8 
dict['I']=9 
dict['J']=10 
dict['K']=11 
dict['L']=12 
dict['M']=13 
dict['N']=14 
# .....其他字母 
def count_(s): 
  p=len(s)-1 
  count=0 
  for x in xrange(len(s)): 
    count+=get(x)*dict[s[p-x]] 
  return count 
def get(p): 
  return 26**p 
print count_('AC')