Python - 删除在另一个子列表中存在的子列表

duplicate_list = [[Aayush, Shyam, John], [Shyam, John], [Henry, Joe], [David, Stefen, Damon], [David, Stefen]] #All the sublist whose data is already present in other sublist are to be removed

new_list = [[Aayush, Shyam, John], [Henry, Joe], [David, Stefen, Damon]]

duplicate_list = [[Aayush, Shyam, John], [Shyam, John], [Henry, Joe], [David, Stefen, Damon], [David, Stefen]] New_list = [sublist for sublist in duplicate_list if not any(set(sublist) <= set(other) for other in duplicate_list if sublist is not other)] #We first check all the lists of the duplicate list through the any() function and then we check for any repeatation with the help of <= operator

def is_sublist(sublist, other): #is_sublist is the function defined return set(sublist) <= set(other) #the functions checks 2 sublists at a time and if the sublist already exists then it returns with `true` feedback and does not consider the extra sublist duplicate_list = [[Aayush, Shyam, John], [Shyam, John], [Henry, Joe], [David, Stefen, Damon], [David, Stefen]] new_list = [sublist for sublist in duplicate_list if not any(is_sublist(sublist, other) for other in duplicate_list if sublist is not other)]

duplicate_list = [[Aayush, Shyam, John], [Shyam, John], [Henry, Joe], [David, Stefen, Damon], [David, Stefen]] #A copy of duplicate list is created to avoid any errors in the original file new_list = duplicate_list[:] #Check each sublist present in the new_list for sublist in duplicate_list: for other in new_list: # Checking of presence of sublist present in other sublist is done if sublist != other and set(sublist).issubset(other): #issubset is used to check presence of one sublist in another sublist # Remove all the repeating sublist new_list.remove(sublist) break #break is used to stop the loop so that it does not keep checking continuosly print(new_list)

duplicate_list = [[Aayush, Shyam, John], [Shyam, John], [Henry, Joe], [David, Stefen, Damon], [David, Stefen]] new_list = [] for sublist in duplicate_list: is_subset = False for other in duplicate_list: if sublist != other and set(sublist).difference(set(other)) == set(): #The difference operation is used to calculate the difference betwen two sets is_subset = True #When the sublist is present in another sublist the result of is_subset will be true break #Once the result is found to be true, the loop is broke and all the other sublist are copied into the new_list if not is_subset: new_list.append(sublist) print(new_list)