编写一个在C语言中打印数字模式的程序

1
2 6
3 7 10
4 8 11 13
5 9 12 14 15

        1
      1 2 3
    1 2 3 4 5
  1 2 3 4 5 6 7
1 2 3 4 5 6 7 8 9
  1 2 3 4 5 6 7
    1 2 3 4 5
      1 2 3
        1

Pattern 1:
i stands for rows and j stands for columns.
5 stands for making pattern for 5 Rows and Columns
Loop for each Row (i)
K is initialized to i
Loop for each Column (j)
Do the Pattern for the current Column (j)
Display the Value of K
Reinitialize the Value of K = k + 5 - j
Pattern 2:
First Row: Display 1
Second Row: Display 1,2,3
Third Row: Display 1,2,3,4,5
Fourth Row: Display 1,2,3,4,5,6,7
Fifth Row: Display 1,2,3,4,5,6,7,8,9
Display the same contents from 4th Row till First Row below the fifth Row.

/* Program to print Numeric Pattern */
#include
int main(){
   int i,j,k;
   printf("Numeric Pattern 1");
   printf("
");
   printf("
");
   for(i=1;i<=5;i++){
      k = i;
      for(j=1;j<=i;j++){
         printf("%d ", k);
         k += 5-j;
      }
      printf("
");
   }
   printf("
");
   printf("Numeric Pattern 2");
   printf("
");
   printf("
");
   for(i = 1;i<=5;i++){
      for(j = i;j<5;j++){
         printf(" ");
      }
      for(k = 1;k<(i*2);k++){
         printf("%d",k);
      }
      printf("
");
   }
   for(i = 4;i>=1;i--){
      for(j = 5;j>i;j--){
         printf(" ");
      }
      for(k = 1;k<(i*2);k++){
         printf("%d",k);
      }
      printf("
");
   }
   getch();
   return 0;
}