PHP如何实现网页截图

PHP实现网页截图的方法：首先下载CutyCapt；然后解压tar包；最后使用代码“public function index(){echo '

';echo date('Y-m-d H:m:s')...}”实现截图即可。</p></blockquote>
<p><img  src="https://img.php.cn/upload/article/202008/15/2020081509330277584.jpg" alt="PHP如何实现网页截图" ></p>
<p>推荐：《<a href="//m.sbmmt.com/course/list/29/type/2.html" target="_blank">PHP视频教程</a>》</p>
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<p id="content_views" class="markdown_views prism-tomorrow-night-eighties"><!-- flowchart 箭头图标 勿删 --><svg xmlns="http://www.w3.org/2000/svg" style="display: none;"><path stroke-linecap="round" d="M5,0 0,2.5 5,5z" id="raphael-marker-block" style="-webkit-tap-highlight-color: rgba(0, 0, 0, 0);"></path></svg></p>
<blockquote><p><strong>如果需要将一个网址的内容做成视图图片输出，则需要辅助工具<code>CutyCapt</code>来实现这一需求</strong></p></blockquote>
<h2>Windows系统</h2>
<ul>
<li>下载CutyCapt<br>CutyCapt下载地址:http://sourceforge.net/projects/cutycapt/files/cutycapt/</li>
<li>解压tar包，看到<code>CutyCapt.exe</code>  不需要再点击安装</li>
<li>代码实现（时间需要20多秒）：</li>
</ul><div class="code" style="position:relative; padding:0px; margin:0px;"><pre class="brush:js;toolbar:false;"> public function index()
    {
        echo &#39;<pre class="brush:php;toolbar:false">&#39;;
        echo date(&#39;Y-m-d H:m:s&#39;).&#39;<br>&#39;;
        $_GET[&#39;url&#39;] = &#39;https://www.aliyun.com/jiaocheng/970387.html&#39;;
        $url=$_GET["url"];
        $imgName = rand(10000,99999);
        $out = &#39;D:/game/&#39;.$imgName.&#39;.png&#39;; //输出图片地址
        $path = &#39;D:/game/CutyCapt.exe&#39;;   //工具存储地址
        $cmd = "$path --url=$url --out=$out";
        echo $cmd.&#39;<br>&#39;;
        system($cmd, $em);
        if(!empty($em)){
            echo &#39;成功了呢&#39;;
        };
        echo date(&#39;Y-m-d H:m:s&#39;).&#39;<br>&#39;;

    }

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