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调用API,对方总是说参数放在BODY里面

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Lepaskan： 2016-08-08 09:06:57

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2773 orang telah melayarinya

请问PHP CURL post json参数如何放在body里面

private function getAccessToken(){

<code>        $url='http://114.215.198.210:8081/api_v1/oauth2/accessToken';
        $postData=array('client_id'=>$this->cliendId,'client_secret'=>$this->client_secret,'grant_type'=>'client_credentials');
        echo $postJosnData = json_encode($postData);
        $ch = curl_init($url);
        curl_setopt($ch, CURLOPT_HEADER, 0);
        curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
        curl_setopt($ch, CURLOPT_POST, 1);
        curl_setopt($ch, CURLOPT_POSTFIELDS, $postJosnData);    
        curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, FALSE);  
        curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, FALSE);  
        $data = curl_exec($ch);
        return $data;
    }
</code>

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没错吧？对方总是说请求参数要放在BODY里面

回复内容：

请问PHP CURL post json参数如何放在body里面

private function getAccessToken(){

<code>        $url='http://114.215.198.210:8081/api_v1/oauth2/accessToken';
        $postData=array('client_id'=>$this->cliendId,'client_secret'=>$this->client_secret,'grant_type'=>'client_credentials');
        echo $postJosnData = json_encode($postData);
        $ch = curl_init($url);
        curl_setopt($ch, CURLOPT_HEADER, 0);
        curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
        curl_setopt($ch, CURLOPT_POST, 1);
        curl_setopt($ch, CURLOPT_POSTFIELDS, $postJosnData);    
        curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, FALSE);  
        curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, FALSE);  
        $data = curl_exec($ch);
        return $data;
    }
</code>

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没错吧？对方总是说请求参数要放在BODY里面

新增下面这句试试

<code> curl_setopt($ch, CURLOPT_HTTPHEADER, array(                   
        'Content-Type: application/json',  
        'Content-Length: ' . strlen($postData))           
    ); </code>

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post请求body一般有两种格式，json和form。你用的json，可能对方用的form

php不懂，不过request的时候是可以把数据放到request body里的，看这个

http://stackoverflow.com/ques...