Bagaimanakah saya boleh memainkan fail .WAV dengan klik butang dalam aplikasi Java saya?

import java.io.File;
import java.io.IOException;

import javax.sound.sampled.AudioFormat;
import javax.sound.sampled.AudioInputStream;
import javax.sound.sampled.AudioSystem;
import javax.sound.sampled.DataLine;
import javax.sound.sampled.LineUnavailableException;
import javax.sound.sampled.SourceDataLine;

public class PlayWAVFileOnClick {

    private static final int BUFFER_SIZE = 128000;
    private File soundFile;
    private AudioInputStream audioStream;
    private AudioFormat audioFormat;
    private SourceDataLine sourceLine;

    public static void main(String[] args) {
        // Instantiate a new PlayWAVFileOnClick object
        PlayWAVFileOnClick player = new PlayWAVFileOnClick();

        // Specify the path to the .wav file
        String soundFilepath = "path/to/beep.wav";

        // Play the sound
        player.playSound(soundFilepath);

        // Close resources after playback
        player.closeResources();
    }

    public void playSound(String filename) {
        try {
            soundFile = new File(filename);
            audioStream = AudioSystem.getAudioInputStream(soundFile);
            audioFormat = audioStream.getFormat();
            DataLine.Info info = new DataLine.Info(SourceDataLine.class, audioFormat);
            sourceLine = (SourceDataLine) AudioSystem.getLine(info);
            
            sourceLine.open(audioFormat);
            sourceLine.start();
            
            byte[] data = new byte[BUFFER_SIZE];
            int readSize = 0;
            
            while ((readSize = audioStream.read(data)) != -1) {
                sourceLine.write(data, 0, readSize);
            }
            
        } catch (IOException | LineUnavailableException e) {
            e.printStackTrace();
        }
    }

    public void closeResources() {
        try {
            sourceLine.drain();
            sourceLine.close();
            audioStream.close();
        } catch (IOException e) {
            e.printStackTrace();
        }
    }
}