Bagi mereka yang baru menggunakan MySQL, termasuk saya sendiri, anda mungkin menemui hasil yang tidak dijangka apabila anda membuat pertanyaan daripada jadual yang mempunyai beberapa nilai nol. Dalam MySQL, null tidak benar atau palsu tetapi tidak diketahui, dan anda tidak boleh membandingkan null dengan null melainkan anda menggunakan operator 'IS NULL' atau 'IS NOT NULL'. Saya mendapati bahawa cara MySQL melayan null bukan sahaja menarik tetapi juga penting untuk difahami. Di sini, saya menunjukkan cara null berkelakuan menggunakan pelbagai fungsi MySQL!
Menyertai Jadual dengan Lajur Yang Mengandungi Nilai Null
NULL dengan INNER JOIN lwn. NULL dengan LEFT JOIN
Katakan terdapat dua jadual, seperti yang diterangkan di bawah:
Nama jadual : guru
id | dept_id | name |
---|---|---|
101 | 1 | Shrivell |
102 | 1 | Throd |
103 | 1 | Splint |
104 | NULL | Spiregrain |
105 | 2 | Cutflower |
106 | NULL | Deadyawn |
Nama jadual : jabatan
id | name |
---|---|
1 | Computing |
2 | Design |
3 | Engineering |
NULL | NULL |
Perhatikan bahawa terdapat nilai nol dalam jadual guru. Apakah yang akan berlaku jika saya menggunakan INNER JOIN untuk menggabungkan kedua-dua jadual ini?
SELECT teachers.name, departments.name AS department FROM teachers INNER JOIN departments ON (teachers.dept_id = departments.id)
Inilah hasilnya
+-----------+------------+ | Name | Department | +-----------+------------+ | Shrivell | Computing | | Throd | Computing | | Splint | Computing | | Cutflower | Design | +-----------+------------+
Perhatikan bahawa dalam keputusan, anda tidak melihat nama dua guru yang jabatan_idnya adalah batal.
Tetapi bagaimana pula dengan menggunakan LEFT JOIN? Jom kita tengok.
Berikut ialah pertanyaan di mana saya hanya menukar 'DALAM' dengan 'KIRI'.
SELECT teachers.name, departments.name AS department FROM teachers LEFT JOIN departments ON (teachers.dept_id = departments.id)
Inilah hasilnya
+------------+------------+ | Name | Department | +------------+------------+ | Shrivell | Computing | | Throd | Computing | | Splint | Computing | | Spiregrain | NULL | | Cutflower | Design | | Deadyawn | NULL | +------------+------------+
Anda akan perasan bahawa semua guru disenaraikan. INNER JOIN tidak mengembalikan rekod dengan nilai nol, tetapi LEFT JOIN akan mengembalikannya.
KENAPA?
Perlu diingat bahawa apabila menggunakan operator kesamaan (=) dengan NULL ke NULL, hasilnya tidak benar atau palsu—ia tidak diketahui. Oleh itu, rekod dengan nilai NULL pada kedua-dua belah perbandingan tidak disertakan dalam set hasil apabila menggunakan INNER JOIN. Walau bagaimanapun, dengan sifat LEFT JOIN, ia memilih SEMUA rekod dari jadual sebelah kiri (iaitu jadual guru dalam kes ini), walaupun dept_id adalah batal. Tidak seperti INNER JOIN, yang akan mengalih keluar rekod sedemikian daripada senarai, LEFT JOIN mengekalkannya.
WUJUD & NULL dan IN & NULL
Kedua-dua EXISTS dan IN tidak mengembalikan rekod dengan nilai nol.
Mari kita pertimbangkan contoh di mana saya mempunyai jadual ini.
Nama jadual: pelanggan
customer_id | first_name | last_name | phone_number |
---|---|---|---|
1 | John | Doe | 123-456-7890 |
2 | Jane | Smith | 987-654-3210 |
3 | Alice | Johnson | NULL |
4 | Bob | Brown | 555-555-5555 |
Nama jadual: pelanggan_2
customer_id | first_name | last_name | phone_number |
---|---|---|---|
1 | John | Doe | 123-456-7890 |
2 | Jane | Smith | NULL |
3 | Alice | Johnson | 111-222-3333 |
4 | Bob | Brown | NULL |
Here is a query:
Using EXISTS to check if a name in b_table exists in a_table.
SELECT * FROM customers AS c1 WHERE EXISTS( SELECT * FROM customers_2 AS c2 WHERE c1.first_name = c2.first_name AND c1.last_name = c2.last_name AND c1.phone_number = c2.phone_number);
Using IN to see if name in b_table is in a_table
SELECT * FROM customers AS c1 WHERE (c1.first_name, c1.last_name, c1.phone_number) IN ( SELECT c2.first_name, c2.last_name, c2.phone_number FROM customers_2 AS c2 );
Both returns the same result
+-------------+------------+-----------+--------------+ | customer_id | first_name | last_name | phone_number | +-------------+------------+-----------+--------------+ | 1 | John | Doe | 123-456-7890 | +-------------+------------+-----------+--------------+
Notice that records with null values are not returned.
WHY?
Because with EXISTS, you can't link columns that are null. For IN, it ignores null values as if they don't exist. Thus, both treat nulls in the same way: neither returns nulls.
** HOWEVER, it's not the same story with NOT EXISTS and NOT IN when dealing with NULL!**
Let's take a look.
I simply swapped EXISTS for NOT EXISTS.
SELECT * FROM customers AS c1 WHERE NOT EXISTS( SELECT * FROM customers_2 AS c2 WHERE c1.first_name = c2.first_name AND c1.last_name = c2.last_name AND c1.phone_number = c2.phone_number);
Here is the result
| customer_id | first_name | last_name | phone_number | |-------------|------------|-----------|---------------| | 2 | Jane | Smith | 987-654-3210 | | 3 | Alice | Johnson | [NULL] | | 4 | Bob | Brown | 555-555-5555 |
Notice that it is returning records with null values. Both Jane and Bob's phone numbers in the customers_2 table are null, but since both phone numbers have values in the customers table, the returned values are not null.
How about using NOT IN?
SELECT * FROM customers AS c1 WHERE (c1.first_name, c1.last_name, c1.phone_number) NOT IN ( SELECT c2.first_name, c2.last_name, c2.phone_number FROM customers_2 AS c2 );
Here is the result
+-------------+------------+-----------+--------------+ | customer_id | first_name | last_name | phone_number | +-------------+------------+-----------+--------------+
Nothing is returned!
Why does NOT EXISTS return null values but NOT IN does not? It's because they both treat null differently. NOT EXISTS is simply the opposite of EXISTS. It returns EVERYTHING that is not returned by EXISTS, including nulls.
However, NOT IN returns records that evaluate to TRUE, but in MySQL, null is neither TRUE nor FALSE—it is unknown.
Let's take a look at the record for Jane Smith with Id2.
When NOT IN is used, it compares:
Jane != Jane OR Smith != Smith OR 987-654-3210 != null.
Jane != Jane -> False
Smith != Smith -> False
987-654-3210 != null -> NULL
False or False or Null evaluates to NULL, so the record doesn't get returned!
Here's a little twist:
What if the first name in the customers table does not match the first name in the customers_2 table?
Let’s compare:
Jane Smith 987-654-3210 (from the customers table) and Jack Smith null (from the customers_2 table).
Here is the result
+-------------+------------+-----------+--------------+ | customer_id | first_name | last_name | phone_number | +-------------+------------+-----------+--------------+ | 2 | Jack | Smith | 987-654-3210 |
What? You see Jack! Doesn't NOT IN fail to evaluate null as either false or true, so the record shouldn't be returned?
Let's analyze it:
Jane != Jack -> True
Smith != Smith -> False
987-654-3210 != null -> NULL
True or False or Null actually returns:
True || False -> True
True || NULL -> True
Therefore, the record gets returned!
If you want to understand how true, false, and null are evaluated, here is the link:
https://dev.mysql.com/doc/refman/8.0/en/logical-operators.html#operator_and
As you can see, it can get quite confusing when it comes to comparing null values.
At the end of the day, I think it's best to explicitly compare null values using IS NULL or IS NOT NULL, which returns true or false as shown below.
SELECT * FROM customers AS c1 WHERE EXISTS( SELECT * FROM customers_2 AS c2 WHERE c1.first_name = c2.first_name AND c1.last_name = c2.last_name AND c1.phone_number = c2.phone_number OR (c1.phone_number IS NULL AND c2.phone_number IS NULL));
Handling null values in MySQL can be quite challenging, requiring careful attention when they are present in your database. It's crucial to conduct explicit null checking to clearly define how null values should be treated. By implementing the strategies I mentioned earlier, such as using IS NULL or IS NOT NULL, you can ensure more predictable and accurate query results.
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