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python下向sqlite插入记录,是否存在过记录的判断不起作用

每次都是返回 False

import sqlite3

conn = sqlite3.connect('urls.db')
cursor = conn.cursor()
cursor.execute('CREATE TABLE IF NOT EXISTS  urls (id integer primary key autoincrement, link text)') 

def url_exists(url):
    sql_cmd = '''select * from urls where link = '%s' ''' % url
    cursor.execute(sql_cmd)
    res = cursor.fetchall()
    if len(res) > 0 :
        print '%s exists' % url
        return True
    else:
        sql_cmd_2 = '''insert into urls(link) values('%s') ''' % url
        cursor.execute(sql_cmd_2)
        print '%s added' % url
        return False
    cursor.close()
    conn.commit()
    conn.close()

url_status = url_exists('example.com')
print url_status
# Python
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  • 高洛峰

    高洛峰2017-04-18 09:06:44

    因为添加之后你直接return True了,数据库没有commit。。。

    import sqlite3
    
    conn = sqlite3.connect('/tmp/urls.db')
    cursor = conn.cursor()
    cursor.execute('CREATE TABLE IF NOT EXISTS  urls (id integer primary key autoincrement, link text)') 
    
    def url_exists(url):
        sql_cmd = '''select * from urls where link = '%s' ''' % url
        cursor.execute(sql_cmd)
        res = cursor.fetchall()
        suc = True
        if len(res) > 0 :
            print '%s exists' % url
            suc = True
        else:
            sql_cmd_2 = '''insert into urls(link) values('%s') ''' % url
            cursor.execute(sql_cmd_2)
            print '%s added' % url
            suc = False
        cursor.close()
        conn.commit()
        conn.close()
        return suc
    
    url_status = url_exists('example.com')
    print url_status

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