How to use php to operate the database to determine whether the table exists

This article mainly introduces the method of using PHP to determine whether a table exists in the database. Interested friends can refer to it. I hope it will be helpful to everyone.

The example of this article describes the method of determining whether a table exists in PHP. The details are as follows:

<?php
//方法一
  mysql_connect(&#39;localhost&#39;,&#39;root&#39;,&#39;2260375&#39;) or die(&#39;can\&#39;t not connect database&#39;);
  if((int)check_table_is_exist(&#39;show databases;&#39;,&#39;test&#39;)==1)
  {
    echo &#39;该表存在&#39;;
  }
  else
  {
    echo &#39;该表不存在&#39;;
  }
  function check_table_is_exist($sql,$find_table)
  {
    $row=mysql_query($sql);
    $database=array();
    $finddatabase=$find_table;
    while ($result=mysql_fetch_array($row,MYSQL_ASSOC))
    {
      $database[]=$result[&#39;Database&#39;];
    }
    unset($result,$row);
    mysql_close();
    /*开始判断表是否存在*/
    if(in_array($find_table,$database))
    {
      return true;
    }
    else
    {
      return false;
    }
  }
//////////////////////////////////////////////方法二
  mysql_connect(&#39;localhost&#39;,&#39;root&#39;,&#39;root&#39;);     
  $result = mysql_list_tables(&#39;database&#39;);     
  $i=0; 
  while($i<mysql_num_rows($result))
  {
  if (&#39;Table_Name&#39; == mysql_tablename($result,$i)) {
    echo &#39;存在&#39;;
      break;
  }             
    $i++;   
  }
  echo &#39;不存在&#39;;
mysql_close();
//////////////////////////////////////方法三
$data  = array();
$dbname = &#39;你要查询的表名&#39;;
mysql_connect(&#39;localhost&#39;, &#39;root&#39;, &#39;&#39;) or die(&#39;Cann\&#39;t connect server!&#39;);
$result = mysql_query(&#39;show databases;&#39;);
While($row = mysql_fetch_assoc($result)){
  $data[] = $row[&#39;Database&#39;];
}unset($result, $row);
mysql_close();
print_r($data);
if (in_array(strtolower($dbname), $data))
  die(&#39;存在&#39;);
else
  die(&#39;不存在&#39;);
?>

Summary: The above is the entire content of this article. I hope it can be useful for everyone's learning. help.

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