Home > Article > Backend Development > PHP code to determine whether the visitor is a search engine or a real user

PHP code to determine whether the visitor is a search engine or a real user

WBOYOriginal: 2016-07-25 09:00:031606browse

/**
* Determine whether the access source is a search engine or a real user
* site bbs.it-home.org
*/
function is_bot()
{
/* This function will check whether the visitor is a search engine robot */
//根据需要扩充此数组
$botlist = array("Teoma", "alexa", "froogle", "Gigabot", "inktomi",
"looksmart", "URL_Spider_SQL", "Firefly", "NationalDirectory",
"Ask Jeeves", "TECNOSEEK", "InfoSeek", "WebFindBot", "girafabot",
"crawler", "bbs.it-home.org", "Googlebot", "Scooter", "Slurp",
"msnbot", "appie", "FAST", "WebBug", "Spade", "ZyBorg", "rabaz",
"Baiduspider", "Feedfetcher-Google", "TechnoratiSnoop", "Rankivabot",
"Mediapartners-Google", "Sogou web spider", "WebAlta Crawler","TweetmemeBot",
"Butterfly","Twitturls","Me.dium","Twiceler");
foreach($botlist as $bot)
{
if(strpos($_SERVER['HTTP_USER_AGENT'],$bot)!==false)
return true; // Is a bot
}
return false; // Not a bot
}
?>

复制代码

Statement：

The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn

Previous article：Simple example of php sphinxNext article：Simple example of php sphinx

See more

PHP code to determine whether the visitor is a search engine or a real user

Related articles