Home  >  Article  >  类库下载  >  Several ways to pass in parameters when running in php command line mode

Several ways to pass in parameters when running in php command line mode

高洛峰
高洛峰Original
2016-10-14 10:20:351102browse
  1. URL method

$param = array();
 
if ($argc > 1) {
    parse_str ( $argv [1], $param );
    foreach ( $param as $k => $v ) {
        echo "define $k=$v\n";
        $param[$k] = $v;
    }
}
 
print_r($param);
 
//运行示例
php sync_t_search.php "name=sjk&city=bj"

2. System built-in variables

//当传入多个或多个参数可选时有很大的局限性
$argv #0为当前执行的文件名
$argc #参数个数

3. System function getopt

//1、个人总结:如果只传一个参数,:(必选)/::(可选)都可
//2、如果传多个参数则要区分可选必选,建议尽量用可选参数并且后面的值不要传入空格
//3、可选参数:标识符存在且有值时,下标才会存在
//4、必选参数:只要标识符存在,下标就会存在(如果取不到值为false)
/**
 * 
php song.php -h"a b" || php song.php -h"a b" 不受空格影响(建议保持一致都不加空格)
array(1) {
  ["h"]=>
  string(3) "a b"
}
 
php song.php -h -a
array(1) {
  ["h"]=>
  string(2) "-a"
}
 
 */
var_dump(getopt('h:a::')); //必选参数,如果参加之间有空格要加引号, 选项后面有空格也不会影响取值,会把他后面的值都当做参数的值
 
/**
php song.php -asong
array(1) {
  ["a"]=>
  string(4) "song"
}
 */
var_dump(getopt('a::h:')); //可选参数,参数必须紧跟在选项后面,否则获取不到

4. System function getopt

//标准输出
fwrite(STDOUT, "Enter your name: ");
echo "\n";
//标准输入
$name = trim(fgets(STDIN));
fwrite(STDOUT, "Hello, $name!");


Statement:
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn

Related articles

See more