How to find the sum of odd numbers in an array in php

Method: 1. Use "$sum=0;" to define a variable to store the calculation results; 2. Use "foreach($arr as $v){}" to loop through the array; 3. In the loop body, check whether the array elements are an odd number, and if so, add them up. The syntax is "if($v%2!=0){$sum =$v;}".

The operating environment of this tutorial: windows7 system, PHP8.1 version, DELL G3 computer

php seeks the array Method of sum of odd numbers

Implementation idea:

• Define a variable assigned value 0 for storage calculation result.

• Use the foreach statement to loop through the array

• In the loop body, check whether the array elements are odd one by one; if they are odd, add them Get up

How to check odd numbers:

• Determine whether the element is divisible by 2, if not, it is an odd number. Syntax:

元素%2!=0

Complete implementation code:

<?php
header("Content-type:text/html;charset=utf-8");
$arr=array(1,2,3,4,5,6,7,8,9);
var_dump($arr);
$sum=0;
foreach($arr as $v){
	if($v%2!=0){
		$sum+=$v;
	}
}
echo "数组中奇数元素之和：".$sum;
?>

It can be seen that in the above example, the odd number The elements are: 1, 3, 5, 7, 9. Let’s use the counter to add it up to see if it is 25

ok, correct!

Recommended learning: "PHP Video Tutorial"

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