Map （exMap:{"name":"abc","sex",'male'}）：
在不知道key的情况下遍历map：
网上说过这种方法：
for(var key in exMap){
Console.write("key:"+key+";value:"+exMap[key]);//经我考证，the key is undefined.So the method is not right.
}
另外一种方法(Good)：
$.each(exMap,function(key,value){
Console.wiite("key:"+key+";value:"+value);
});
在知道的key的情况下遍历map自然就跟数组一样的访问罗，这里就不说了。
List访问很简单：
for(var i =0;ivalue = list[i]
}
参考(jquery筛选数组之grep、each、inArray、map的用法及遍历json对象 ):
http://sjolzy.cn/jquery-selection-and-use-of-an-array-of-grepeachinArraymap-json-object-traversal.html
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