1. Implementation effect
Requirements: Receive a folder path from the keyboard, and print all the files in the folder and the names of the folders hierarchically.
For example: Print all the files in the folder and the names of the folders hierarchically.
2. Implement logic
Get all files and folders, return the File array, and traverse the array. Whether it is a file or a folder, it needs to be printed directly. If it is a folder, call it recursively.
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3. Implementation code
aaa is a folder, which contains bbb.txt, ccc.txt, Files such as ddd.txt have folders such as eee. There are fff.txt and ggg.txt in eee, which print out the hierarchy.
For example:
The code is as follows:
public class Test4 {
public static void main(String[] args) {
File dir = getDir(); //获取文件夹路径
printLev(dir,0);
}
/*
* 从键盘接收一个文件夹路径
* 1,返回值类型File
* 2,参数列表无
*/
public static File getDir() {
//1,创建键盘录入对象
Scanner sc = new Scanner(System.in);
System.out.println("请输入一个文件夹路径:");
//2,定义一个无限循环
while(true) {
//3,将键盘录入的结果存储并封装成File对象
String line = sc.nextLine();
File dir = new File(line);
//4,对File对象判断
if(!dir.exists()) {
System.out.println("您录入的文件夹路径不存在,请输入一个文件夹路径:");
}else if(dir.isFile()) {
System.out.println("您录入的是文件路径,请输入一个文件夹路径:");
}else {
//5,将文件夹路径对象返回
return dir;
}
}
}
public static void printLev(File dir,int lev) {
//1,把文件夹中的所有文件以及文件夹的名字按层级打印
File[] subFiles = dir.listFiles();
//2,遍历数组
for (File subFile : subFiles) {
for(int i = 0; i <= lev; i++) {
System.out.print("\t");
}
//3,无论是文件还是文件夹,都需要直接打印
System.out.println(subFile);
//4,如果是文件夹,递归调用
if(subFile.isDirectory()) {
//printLev(subFile,lev + 1);
printLev(subFile,++lev);
}
}
}
}For more related articles and tutorials, please visit: Java Language Introduction
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