JDBC中如何处理日期？

You can insert date values in SQL using the date datatype, The java.sql.Date class maps to the SQL DATE type.

The PreparedStatement interface provides a method named setDate(). Using this you can insert date into a table. This method accepts two parameters −

• An integer representing the parameter index of the place holder (?) to which we need to set date value.

• a Date object representing the date value to be passed. The constructor of java.sql.Date class accepts a variable of long type representing the number of milliseconds from the epoch (standard base time I.e. January 1, 1970, 00:00:00 GMT).

Example

Assume we have created a table named Emp in MySQL database with the following description −

+----------+--------------+------+-----+---------+-------+
| Field    | Type         | Null | Key | Default | Extra |
+----------+--------------+------+-----+---------+-------+
| Name     | varchar(255) | YES  |     | NULL    |       |
| DOB      | date         | YES  |     | NULL    |       |
| Location | varchar(255) | YES  |     | NULL    |       |
+----------+--------------+------+-----+---------+-------+

Following JDBC program inserts records in to this table −

import java.sql.Connection;
import java.sql.DriverManager;
import java.sql.PreparedStatement;
import java.sql.ResultSet;
import java.sql.Statement;
import java.sql.Date;
public class InsertingDate {
   public static void main(String args[])throws Exception {
      //Getting the connection
      String mysqlUrl = "jdbc:mysql://localhost/sampleDB";
      Connection con = DriverManager.getConnection(mysqlUrl, "root", "password");
      System.out.println("Connection established......");
      //Inserting values to a table
      String query = "INSERT INTO Emp(Name, DOB, Location) VALUES (?, ?, ?)";
      PreparedStatement pstmt = con.prepareStatement(query);
      pstmt.setString(1, "Amit"); pstmt.setDate(2, new Date(622790105000L));
      pstmt.setString(3, "Hyderabad");
      pstmt.execute();
      pstmt.setString(1, "Sumith"); pstmt.setDate(2, new Date(620611200000L));
      pstmt.setString(3, "Vishakhapatnam");
      pstmt.execute();
      pstmt.setString(1, "Sudha");
      pstmt.setDate(2, new Date(336614400000L));
      pstmt.setString(3, "Vijayawada");
      pstmt.execute();
      System.out.println("Records inserted......");
   }
}

Output

Connection established......
Records inserted......

如果你在MySQL数据库中验证表格，你可以观察到表格的内容如下：

mysql> select * from Emp;
+--------+------------+----------------+
| Name   | DOB        | Location       |
+--------+------------+----------------+
| Amit   | 1989-09-26 | Hyderabad      |
| Sumith | 2019-03-19 | Vishakhapatnam |
| Sudha  | 2019-03-19 | Vijayawada     |
+--------+------------+----------------+
3 rows in set (0.00 sec)

以上就是JDBC中如何处理日期？的详细内容，更多请关注php中文网其它相关文章！