C程序用于比较两个矩阵是否相等

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2023-08-31 13:13:06 1010浏览

C程序用于比较两个矩阵是否相等

用户必须输入两个矩阵的顺序以及两个矩阵的元素。然后,比较这两个矩阵。

如果矩阵元素和大小都相等,则表明两个矩阵相等。

如果矩阵大小相等但元素相等不相等,则显示矩阵可以比较,但不相等。

如果大小和元素不匹配,则显示矩阵无法比较。

程序

以下是C程序,用于比较两个矩阵是否相等 -

#include <stdio.h>
#include <conio.h>
main(){
   int A[10][10], B[10][10];
   int i, j, R1, C1, R2, C2, flag =1;
   printf("Enter the order of the matrix A

"); scanf("%d %d", &R1, &C1); printf("Enter the order of the matrix B

"); scanf("%d %d", &R2,&C2); printf("Enter the elements of matrix A

"); for(i=0; i<R1; i++){ for(j=0; j<C1; j++){ scanf("%d",&A[i][j]); } } printf("Enter the elements of matrix B

"); for(i=0; i<R2; i++){ for(j=0; j<C2; j++){ scanf("%d",&B[i][j]); } } printf("MATRIX A is

"); for(i=0; i<R1; i++){ for(j=0; j<C1; j++){ printf("%3d",A[i][j]); } printf("

"); } printf("MATRIX B is

"); for(i=0; i<R2; i++){ for(j=0; j<C2; j++){ printf("%3d",B[i][j]); } printf("

"); } /* Comparing two matrices for equality */ if(R1 == R2 && C1 == C2){ printf("Matrices can be compared

"); for(i=0; i<R1; i++){ for(j=0; j<C2; j++){ if(A[i][j] != B[i][j]){ flag = 0; break; } } } } else{ printf(" Cannot be compared

"); exit(1); } if(flag == 1 ) printf("Two matrices are equal

"); else printf("But,two matrices are not equal

"); }

输出

当执行上述程序时,会产生以下结果 -

Run 1:
Enter the order of the matrix A
2 2
Enter the order of the matrix B
2 2
Enter the elements of matrix A
1
2
3
4
Enter the elements of matrix B
1
2
3
4
MATRIX A is
   1 2
   3 4
MATRIX B is
   1 2
   3 4
Matrices can be compared
Two matrices are equal

Run 2:
Enter the order of the matrix A
2 2
Enter the order of the matrix B
2 2
Enter the elements of matrix A
1
2
3
4
Enter the elements of matrix B
5
6
7
8
MATRIX A is
   1 2
   3 4
MATRIX B is
   5 6
   7 8
Matrices can be compared
But,two matrices are not equal

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