C程序以X形式显示数字

参考下面的算法，编写C程序以显示X形状的数字。

算法

Step 1: Start
Step 2: Declare variables
Step 3: Read number of rows
Step 4: for loop satisfies

• if(i==j || i+j==rows-1)
  • print i+1
• Print " "

The logic to print numbers in X pattern is as follows −

for(i=0;i<rows;i++){
   for(j=0;j<rows;j++){
      if(i==j || i+j==rows-1){
         printf("%d",i+1);
      }else{
         printf(" ");
      }
   }
   printf("
");
}

Program

Following is the C program to display the numbers in X pattern −

#include<stdio.h>
main(){
   int i,j,rows;
   printf("Enter number of rows:
");
   scanf("%d",&rows);
   for(i=0;i<rows;i++){
      for(j=0;j<rows;j++){
         if(i==j || i+j==rows-1){
            printf("%d",i+1);
         }else{
            printf(" ");
         }
      }
      printf("
");
   }
}

输出

当上述程序被执行时，它产生以下结果 −

Enter number  of rows:10
1           1
  2        2
    3    3
      4 4
       55
       66
      7 7
    8     8
  9        9
10          10

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