How to determine whether an array contains an array in php

Steps: 1. Define a variable and assign it to 0, with the syntax "$f=0;"; 2. Use a foreach loop to traverse the outer array elements of the two-dimensional array, with the syntax "foreach(array as $ v){...}"; 3. In the loop body, determine whether the outer element is of array type. If so, set the value of "$f" to 1 and jump out of the loop. The syntax is "if(is_array($v )){$f=1;break;}"; 4. After the loop ends, determine whether the value of "$f" is 1. If so, the array contains a subarray.

The operating environment of this tutorial: windows7 system, PHP version 8.1, DELL G3 computer

php determines an array Steps to include subarrays

Step 1: Define a variable and assign the value to 0

$f=0;

Step 2: Use the foreach statement Loop through the outer array elements of the two-dimensional array

foreach($arr as $v){ //循环体代码 }

Traverse the given $arr array, and assign the current outer array value to $v in each loop.

Step 3: In the loop body, use the is_array() function to determine whether the outer element is an array type

• If it is an array type, Then set the value of variable $f to 1 and use the break statement to jump out of the loop.

if(is_array($v)){ $f=1; break; }

Step 4: After the loop ends, determine whether the value of variable $f is 1

• If 1, the array contains the subarray

• If not 1, the array does not contain the subarray

Recommended learning: "PHP Video Tutorial"

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