How to remove the content after the specified position in php

Removal method: 1. Use the "substr_replace($str,'', position value)" statement to replace all characters after the specified position in the string with null characters, thereby removing all characters; 2. Use The "array_splice($arr, position value)" statement can remove all elements after the specified position in the array.

The operating environment of this tutorial: windows7 system, PHP7.1 version, DELL G3 computer

php realizes two ways of removing the content after specifying the location Method:

• Use substr_replace() function

• Use array_splice() function

1. substr_replace() function

Use substr_replace() to remove all characters after the specified position in the string (just set the replacement value to a null character)

"; echo "去掉第2个字符后的内容".substr_replace($str, $replace, 2)."
"; echo "去掉第3个字符后的内容".substr_replace($str, $replace, 3)."
"; echo "去掉第4个字符后的内容".substr_replace($str, $replace, 4)."
"; echo "去掉第5个字符后的内容".substr_replace($str, $replace, 5)."
"; echo "去掉第6个字符后的内容".substr_replace($str, $replace, 6)."
"; ?>

2. array_splice() function

Use array_splice() to remove all elements after the specified position in the array

Example: There is this An array:

Delete the content after the first element of the array

echo "删除数组第1个元素后的内容：" ; array_splice($arr,1); var_dump($arr);

Delete the second element of the array Content after

echo "删除数组第2个元素后的内容：" ; array_splice($arr,2); var_dump($arr);

Delete the content after the 3rd element of the array

echo "删除数组第3个元素后的内容：" ; array_splice($arr,3); var_dump($arr);

Delete the 4th element of the array The following content

echo "删除数组第4个元素后的内容：" ; array_splice($arr,4); var_dump($arr);

Recommended learning: "PHP Video Tutorial"

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