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This article will share with you a logic interview question (with analysis) whose wrong answer has spread all over the Internet. You can analyze it against yourselves to see if you can answer it correctly!
100 people answered five questions, 81 people answered the first question correctly, 91 people answered the second question correctly, 85 people answered the third question correctly, and 79 people answered the fourth question correctly. , 74 people answered the fifth question correctly.
People who answer three or more questions correctly are considered to have passed. So how many of these 100 people have passed?
First consider if there are only two questions AB, 100 people, first reaction It's done in a collection way.
There are only the above three situations in total. The first one is illegal if the number of people is greater than 100, so only the latter two situations exist.
The following conclusion can be drawn:
There are at least 72 people and a maximum of 81 people who answered questions AB at the same time;
At the same time The maximum number of people who got questions AB and AB wrong was 9 people, and the minimum number was 0 people.
It seems that we have found the pattern, so we will further expand the data scale according to this idea and consider the three ABC questions.
First consider the relationship between each two questions.
Then synthesize the relationship between the three questions. Wait, it seems a bit complicated. This is not linear complexity. Sorry, little K’s IQ is a bit insufficient and he is autistic.
Is Little K ready to give up? NO, never say give up. Sometimes, don’t hit the wall and never look back. Based on Xiao K’s years of experience, if the pattern you find is not obvious or very complicated, it usually means you are on the wrong track, so you should consider switching your way of thinking at this time.
The above are all positive thinking, but it is difficult to deal with, so you can think in reverse.
As long as you make 3 wrong questions, you will fail. There are 19 9 15 21 26 = 90 wrong questions in total. Then 90/3 = 30, then at most 30 people will fail. , so at least 70 people pass, perfect, and call it a day.
Wait always feels a bit weird, not because it is too simple, but because my intuition about the amount of information tells me that this solution ignores a lot of information.
Only the total number is used, but the distribution of the number of wrong questions for the 5 questions is not used. Then just tell you that there are 90 errors in total. Why do you have to tell the specific number separately? Is this really just misleading information?
According to the above solution, since you don’t care about the specific distribution, use extreme thinking to construct special data. For example, all wrong questions are concentrated in question A.
There are still 90 questions wrong in total, but everyone got 4 questions right, so 100 people should have passed, and they are autistic again.
At this time, I think there should be a barrage spirit about to jump out.
Little K: What you said makes sense, but I am speechless.
I won’t bullshit you, let’s think about it further. This counterexample illustrates one point: wrong questions cannot be shared evenly at will, so let’s start from this point.
First look at the distribution of errors.
How to distribute these wrong questions to the most people.
For the convenience of analysis, let’s first write a simple example. For example, the distribution of wrong questions is 7, 8, 9, 10, and 11.
The first allocation:
Assign A, B, and C to 7 people
Assign C, D, Assign E to 2 people
Assign B, D, and E to 1 person
A total of 7 2 1=10 people can be assigned.
In the second type, priority is given to B, C, and D, a total of 11 people.
The third type, priority is given to C, D, and E, a total of 12 people.
#Here we have discovered the pattern. Prioritizing the three largest channels will get more people. During the allocation process, the largest three orders will change dynamically, which inspires the idea of greed.
Sort the wrong questions from largest to smallest;
Assign the top 3 largest questions to one person each time, and then reorder.
Repeat the above steps until finally no three numbers that are not 0 can be found, that is, it becomes X,0,0,0,0 or X,Y,0,0,0.
Conversion problem: There are 5 rectangles, the order can be arbitrary. To cut out N rectangles with a width of 3, the overall superposition must be as high as possible. What is the highest?
You taste it, you taste it carefully, is this the same problem? So start with the top 3 and chip away at it, haha.
Back to the original question, how many people are there at least? Pass code test results.
8.1 Code Implementation
int main() { int a[5], ans = 0; for (int i = 0; i < 5; ++i) { cin >> a[i]; } sort(a, a + 5, compare); while (a[2] > 0) { a[0]--; a[1]--; a[2]--; sort(a, a + 5, compare); ans++; for (int i = 0; i < 5; ++i) { cout << a[i] << " "; } cout << endl; } cout << "ans=" << ans << endl; return 0; }
8.2 Data Test
25 20 18 15 9 24 19 17 15 9 23 18 16 15 9 22 17 15 15 9 21 16 15 14 9 20 15 14 14 9 19 14 14 13 9 18 13 13 13 9 17 13 12 12 9 16 12 12 11 9 15 11 11 11 9 14 11 10 10 9 13 10 10 9 9 12 9 9 9 9 11 9 9 8 8 10 8 8 8 8 9 8 8 7 7 8 7 7 7 7 7 7 7 6 6 6 6 6 6 6 6 6 5 5 5 5 5 5 5 4 5 4 4 4 4 4 4 4 3 3 3 3 3 3 3 3 3 2 2 2 2 2 2 2 1 2 1 1 1 1 1 1 1 0 0 0 0 0 0 0 ans=30
So at most 30 people fail, and at least 70 people pass. Although the answers are the same, the way of thinking is different.
You should think more deeply about seemingly simple questions, maybe you will find different conclusions. And don’t easily believe other people’s analysis. 90% of the people on the Internet are wrong about this issue. You can also check whether my analysis is rigorous. If you have any questions, please leave a message and give feedback. Thank you.
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