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In mysql, the having clause is used to filter various data after grouping. It is usually used in conjunction with "group by". This statement makes up for the shortcoming that the where keyword cannot be used in conjunction with aggregate functions.
The operating environment of this tutorial: windows10 system, mysql8.0.22 version, Dell G3 computer.
The reason for adding the HAVING clause in SQL is that the WHERE keyword cannot be used with aggregate functions.
HAVING clause allows us to filter each group of data after grouping.
SQL HAVING syntax
SELECT column_name, aggregate_function(column_name) FROM table_name WHERE column_name operator value GROUP BY column_name HAVING aggregate_function(column_name) operator value;
Demo database
In this tutorial, we will use the RUNOOB sample database.
The following is the data selected from the "Websites" table:
+----+--------------+---------------------------+-------+---------+ | id | name | url | alexa | country | +----+--------------+---------------------------+-------+---------+ | 1 | Google | https://www.google.cm/ | 1 | USA | | 2 | 淘宝 | https://www.taobao.com/ | 13 | CN | | 3 | 菜鸟教程 | http://www.runoob.com/ | 4689 | CN | | 4 | 微博 | http://weibo.com/ | 20 | CN | | 5 | Facebook | https://www.facebook.com/ | 3 | USA | | 7 | stackoverflow | http://stackoverflow.com/ | 0 | IND | +----+---------------+---------------------------+-------+---------+
The following is the data from the "access_log" website access record table:
mysql> SELECT * FROM access_log; +-----+---------+-------+------------+ | aid | site_id | count | date | +-----+---------+-------+------------+ | 1 | 1 | 45 | 2016-05-10 | | 2 | 3 | 100 | 2016-05-13 | | 3 | 1 | 230 | 2016-05-14 | | 4 | 2 | 10 | 2016-05-14 | | 5 | 5 | 205 | 2016-05-14 | | 6 | 4 | 13 | 2016-05-15 | | 7 | 3 | 220 | 2016-05-15 | | 8 | 5 | 545 | 2016-05-16 | | 9 | 3 | 201 | 2016-05-17 | +-----+---------+-------+------------+ 9 rows in set (0.00 sec)
SQL HAVING instance
Now we want to find websites with total visits greater than 200.
We use the following SQL statement:
SELECT Websites.name, Websites.url, SUM(access_log.count) AS nums FROM (access_log INNER JOIN Websites ON access_log.site_id=Websites.id) GROUP BY Websites.name HAVING SUM(access_log.count) > 200;
The output result of executing the above SQL is as follows:
Recommended learning: mysql video Tutorial
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