How to use JavaScript to determine whether it is a palindrome number

Method: 1. Use toString() and split() to convert the number into an array; 2. Use reserve() to flip the order of the array elements; 3. Use join() and Number() to convert the flipped array Convert to a number; 5. Use the "===" operator to compare whether the original number and the flipped number are equal. If they are equal, it is a palindrome number.

The operating environment of this tutorial: windows7 system, javascript version 1.8.5, Dell G3 computer.

Palindromes refer to integers that read the same in forward order (from left to right) and reverse order (from right to left).

For example, "121" is a palindrome number.

So how to use JavaScript to determine whether it is a palindrome?

Implementation idea: Use array

• First convert a number into a string

• Then convert the string into Split into characters and store them in an array, that is, convert them into a character array

• Then use the reserve() method to flip the array and reverse the order of the elements in the array

• Then convert the flipped array into numbers

• Finally use===to compare to see if the original number and the flipped number are equal , if equal, it is a palindrome number.
  

Implementation code:

var x=121; var str = x.toString() //转化为字符串 var arr = str.split('') //转化为数组 var res = Number(arr.reverse().join('')) if(x===res){ console.log(x +"是一个回文数"); }else{ console.log(x +"不是一个回文数"); }

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