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How to debug sql statement errors in php: 1. Debug PHP SQL errors through the die statement; 2. Debug PHP SQL errors through the "mysql_error" statement.
The operating environment of this article: windows7 system, PHP7.1 version, DELL G3 computer
How to debug sql statement errors in php?
Debug PHP SQL errors through die and mysql_error statements
1. Code
<!--处理文件代码-->
<?php
$conn=mysql_connect('localhost','root','root') or die("与服务器连接失败!");
mysql_select_db('db_database22',$conn) or die("没有找到数据库!");
if($_POST[Submit]=="提交"){
$admin=$_POST[admin];//获取提交的用户名
$pass=$_POST[pass];//获取提交的密码
$dates=date("Y-m-d H:i:s");//定义当前时间
$query="insert into user (admin,password,dates) values('$admin','$pass','$dates')";//编写添加语句
$result=mysql_query($query,$conn) or die(mysql_error()); //执行添加语句，并返回错误信息
if($result){
echo "<script>alert('添加成功！'); window.location.href='index.php';</script>";
}else{
echo "添加失败!!";
}
}
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=gb2312" />
<title>SQL语句错误</title>
</head>
<style type="text/css">
<!--
.STYLE1 {color: #FF0000}
-->
</style>
<body>
<!--表单提交页，设置的表单元素-->
<form name="form1" method="post" action="index.php">
<table width="240" border="1" cellpadding="1" cellspacing="1" bordercolor="#FFFFFF" bgcolor="#FF0000">
<tr>
<td width="80" align="right" bgcolor="#FFFFFF"><span class="STYLE1">管理员：</span></td>
<td width="147" bgcolor="#FFFFFF"><input name="admin" type="text" id="admin" size="20"></td>
</tr>
<tr>
<td align="right" bgcolor="#FFFFFF"><span class="STYLE1">密码：</span></td>
<td bgcolor="#FFFFFF"><input name="pass" type="password" id="pass" size="20"></td>
</tr>
<tr>
<td colspan="2" align="center" bgcolor="#FFFFFF"><input type="submit" name="Submit" value="提交"></td>
</tr>
</table>
</form>
</body>
</html>
2. Running results
Unknown column 'password' in 'field list'
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