What is the program to determine leap year in Python?

Python program to determine leap year: A leap year is a hundred years that is divisible by 400, a leap year is a hundred years that is not divisible by 4, the code is [if (year % 400) == 0&&if (year % 4) = = 0].

The operating environment of this tutorial: Windows 7 system, python version 3.9, DELL G3 computer.

Python program to determine leap year:

The following example is used to determine whether the year entered by the user is a leap year:

Example

# -*- coding: UTF-8 -*-
 
# Filename : test.py
# author by : www.runoob.com
 
year = int(input("输入一个年份: "))
if (year % 4) == 0:
   if (year % 100) == 0:
       if (year % 400) == 0:
           print("{0} 是闰年".format(year))   # 整百年能被400整除的是闰年
       else:
           print("{0} 不是闰年".format(year))
   else:
       print("{0} 是闰年".format(year))       # 非整百年能被4整除的为闰年
else:
   print("{0} 不是闰年".format(year))

We can also use embedded if statements to achieve:

The output result of executing the above code is:

输入一个年份: 2000
2000 是闰年

输入一个年份: 2011
2011 不是闰年

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