Home>Article>Web Front-end> JavaScript prototype and inheritance are a must for interviews
##Related free learning recommendations:This article starts from the following aspectsjavascript( Video)
var o1 = {name: 'o1'} var o2 = new Object({name: 'o2'})2. Through the constructor
var M = function(name){ this.name = name } var o3 = new M('o3')3.Object.create
var o4 = Object.create(p)2 Tips to remember the prototype chain
Memory always There are rules. For example, when you learn trigonometric functions in high school, you need to memorize a lot of formulas. If you force yourself to memorize all the formulas, it will easily become confusing. However, if you memorize the core points, the rest of the formulas only require a little derivation. The same goes for the prototype chain. If you remember a few points at the beginning, you won't get confused later. Key concepts in the prototype chain:constructor,instance,constructor,__ proto__,prototype, first of all Remember their relationship
Please keep in mind the above three points, the complete inheritance summarized later is closely related to this
In factConstructor,Instance,constructor,__ proto__,prototypeare already related in the above example and 3 points That’s it in the introduction. Let’s review again
newAddconstructor, and the generated object is an instance.
o3.__proto__ === M.prototype //true o3.prototype //undefined o3.__proto__ === M.prototype //true
o3.constructor === M.prototype.constructor // true o3.constructor === M //true
Summary After clarifying the relationship between these keywords, the prototype chain will become much clearer3 instanceof simulation implementation
[] instanceof Array // true
. That is, the left side is the object and the right side is the type. instanceof is to determine whether the prototype of the right type is on the prototype chain of the left instance, as shown in the following example
[].__proto__ === Array.prototype //true Array.prototype.__proto__ === Object.prototype //true Object.prototype__proto__ //nullThen implement instanceof based on this idea, you will definitely be more impressed
new process happened What?function myInstanceof2(left, right){ if(left === null || left === undefined){ return false } if(right.prototype === left.__proto__) { return true } left = left.__proto__ return myInstanceof2(left, right) } console.log(myInstanceof2([], Array))4 new simulation implementation (brief version)
of this empty object is assigned to the prototypeof the constructor
// 构造函数 function M(name){ this.name = name } // 原生new var obj = new M('123') // 模拟实现 function create() { // 生成空对象 let obj = {} // 拿到传进来参数的第一项,并改变参数类数组 let Con = [].shift.call(arguments) // 对空对象的原型指向赋值 obj.__proto__ = Con.prototype // 绑定this //(对应下面使用来说明:Con是参数第一项M, // arguments是参数['123'], // 就是 M方法执行,参数是'123',执行这个函数的this是obj) let result = Con.apply(obj, arguments) return result instanceof Object ? result : obj } var testObj = create(M, '123') console.log('testObj', testObj)
// 构造方法方式 function Parent1(){ this.name = 'Parent1' } Parent1.prototype.say = function () { alert('say') } function Child1(){ Parent1.call(this) this.type = 'type' } var c1 = new Child1() c1.say() //报错
Thinking: Why does call implement inheritance? What is the essence of call?
// 原型 function Parent2(){ this.name = 'Parent2' this.arr = [1,2] } Parent2.prototype.say = function () { alert('say') } function Child2(){ // Parent2.call(this) this.type = 'type' } Child2.prototype = new Parent2() var c21 = new Child2() var c22 = new Child2() c21.say() c21.arr.push('9') console.log('c21.arr : ', c21.arr) console.log('c22.arr : ', c22.arr)
Thinking: Why is it written like this to be the same reference?
Combined inheritance 1
Thinking: Is there no problem if I write like this?function Parent3(){ this.name = 'Parent3' this.arr = [1,2] } Parent3.prototype.say = function () { alert('say') } function Child3(){ Parent3.call(this) this.type = 'type' } Child3.prototype = new Parent3() var c31 = new Child3() var c32 = new Child3() c31.say() c31.arr.push('9') console.log('c31.arr : ', c31.arr) console.log('c31.arr : ', c32.arr)
答 : 生成一个实例要执行 Parent3.call(this) , new Child3(),也就是Parent3执行了两遍。
改变上例子 的
Child3.prototype = new Parent3()
为
Child3.prototype = Parent3.prototype
缺点 : 很明显,无法定义子类构造函数原型私有的方法
组合继承优化3 再次改变上例子 的
Child3.prototype = Parent3.prototype
为
Child3.prototype = Object.create(Parent3.prototype)
问题就都解决了。 因为Object.create的原理是:生成一个对象,这个对象的proto, 指向所传的参数。
思考 :是否还有疏漏?一时想不起来的话,可以看下这几个结果
console.log(c31 instanceof Child3) // true console.log(c31 instanceof Parent3) // true console.log(c31.constructor === Child3) // false console.log(c31.constructor === Parent3) // true
所以回想起文章开头所说的那几个需要牢记的点,就需要重新赋值一下子类构造函数的constructor: Child3.prototype.constructor = Child3,完整版如下
function Parent3(){ this.name = 'Parent3' this.arr = [1,2] } Parent3.prototype.say = function () { alert('say') } function Child3(){ Parent3.call(this) this.type = 'type' } Child3.prototype = Object.create(Parent3.prototype) Child3.prototype.constructor = Child3 var c31 = new Child3() var c32 = new Child3() c31.say() c31.arr.push('9') console.log('c31.arr : ', c31.arr) console.log('c31.arr : ', c32.arr) console.log('c31 instanceof Child3 : ', c31 instanceof Child3) console.log('c31 instanceof Parent3 : ', c31 instanceof Parent3) console.log('c31.constructor === Child3 : ', c31.constructor === Child3) console.log('c31.constructor === Parent3 : ', c31.constructor === Parent3)
5 es6的继承
class Parent{ constructor(name) { this.name = name } getName(){ return this.name } } class Child{ constructor(age) { this.age = age } getAge(){ return this.age } }
es6继承记住几个注意事项吧
注意写了extends关键字,constructor中就必须写super()
,打印结果如下:
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