The string end mark is "\0", and 0 is the ASCII code representation of "\0", which is the first ASCII code. The ASCII code of the number 0 is 48, so you need to use " /0" ends.
#'\0' is the end mark of the string array.
And 0 is the ASCII code representation of '\0', which is the first ASCII code. The ASCII code of the number 0 is 48, so when writing a program, you must end it with '\0', such as char a[3 ] = {'h','i','\0'}, or directly char a[] = "hi", the compiler will think it is a string array and ends with '\0'.
When debugging the program, you can see that there is 0 in the memory. This is the representation of the ASCII code and can also be regarded as anunsigned inttype.
Application reference of strings:
1. Concatenation operationconcat(s1,s2,s3…sn)is equivalent tos1 s2 s3…sn.
Example:concat('11','aa')='11aa';
2. Find the substring.Copy(s,I,I)Extract a substring of length l starting from the I-th character from the string s.
Example:copy(‘abdag’,2,3)=’bda’
3. Delete the substring. The procedure Delete(s,I,l) deletes the substring of length l starting from the I-th character from the string s.
Example:s:=’abcde’;delete(s,2,3);Results:=’ae’
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