How to compare the size of strings in java

Can be achieved using the compareTo() method. This method is used to determine whether a string is greater than, equal to, or less than another string. The size of strings is determined based on their order in the dictionary.

Syntax:

Str1.compareTo(Str2);

It returns an int type value. If Str1 is equal to the parameter string Str2, 0 is returned; if Str1 is lexicographically smaller than the parameter string Str2, the return value is less than 0; if Str1 is lexicographically greater than the parameter string Str2, the return value is greater than 0.

The compareto method in java returns the difference between the ASCII codes of the two strings before and after the comparison.

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Example:

String a="a",b="b";
System.out.println(a.compareto.b);

then output -1;

if a=" a", b="a", then output 0;

If a="b", b="a", then output 1;

Single characters are compared in this way, if the string is relatively long Woolen cloth?

If a="ab",b="b", then output -1;

If a="abcdef",b="b", then output -1;

In other words, if the first letters of the two strings are different, this method returns the difference in the ASCII code of the first letters.

What if the first letters are the same? ?

If a="ab", b="a", output 1;

If a="abcdef", b="a", output 5;

If a="abcdef", b="abc" outputs 3;

If a="abcdef", b="ace" outputs -1;

is the two strings participating in the comparison If the first characters are the same, compare the next characters until there is a difference, and return the ASC code difference of the different characters. If the two strings are not the same length, and the characters that can participate in the comparison are exactly the same, return two The length difference of strings.

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